1. Hydrogen cyanide is a highly poisonous, volatile liquid. It can be prepared by the reaction. CH4(g) + NH3(g) → HCN(g) + 3H2(g) 128.4 kJ Calculate the enthalpy change, AH, using the following equations: copper form N2(g) + 3H2(g) → 2NH3(g) ΔΗ- -91.8 kJ C(graphite) + 2H2(g) → CH48) AH = -74.9 kJ H2(g) + 2C(graphite) + N2(g) → 2HCN (g) AH = 270.3 kJ %3D

Chemistry for Engineering Students
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Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
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Problem 9.73PAE: 9.73 Without looking up any numerical data or doing calculations, predict whether the enthalpy...
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1.
Hydrogen cyanide is a highly poisonous, volatile liquid. It can be prepared by the reaction.
CH4(g) + NH3(g) → HCN(g) + 3H2(g)
Calculate the enthalpy change, AH, using the following equations:
copper forme
N2(g) + 3H2(g) → 2NH3(g)
AH = -91.8 kJ
C(graphite) + 2H2(g) → CH4(g)
AH = -74.9 kJ
H2(g) + 2C(graphite) + N2(g) → 2HCN (g)
AH = 270.3 kJ
Transcribed Image Text:1. Hydrogen cyanide is a highly poisonous, volatile liquid. It can be prepared by the reaction. CH4(g) + NH3(g) → HCN(g) + 3H2(g) Calculate the enthalpy change, AH, using the following equations: copper forme N2(g) + 3H2(g) → 2NH3(g) AH = -91.8 kJ C(graphite) + 2H2(g) → CH4(g) AH = -74.9 kJ H2(g) + 2C(graphite) + N2(g) → 2HCN (g) AH = 270.3 kJ
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