1. In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 10 mL 4.0 M acetone + 10 mL 1.0 M HCl + 10 mL 0.0050 M 1₂ + 20 mL H₂O a. How many moles of acetone were in the reaction mixture? Recall that, for a component A, no. moles A = MA X V, where MA is the molarity of A and V is the volume in liters of the solution of A that was used. b. What was the molarity of acetone in the reaction mixture? The volume of the mixture was 50 mL, 0.050 L, and the number of moles of acetone was found in Part a. Again, MA= moles acetone no. moles A V of soln. in liters

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Chapter3: Statistical Tests With Excel
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1. In a reaction involving the iodination of acetone, the following volumes were used to make
reaction mixture:
10 mL 4.0 M acetone + 10mL 1.0 M HCl + 10 mL 0.0050 M 1₂ + 20 mL H₂O
a. How many moles of acetone were in the reaction mixture? Recall that, for a component A, no.
moles A = MA X V, where MA is the molarity of A and V is the volume in liters of the solution of A
that was used.
b. What was the molarity of acetone in the reaction mixture? The volume of the mixture was 50 mL,
0.050 L, and the number of moles of acetone was found in Part a. Again,
MA =
moles acetone
no. moles A
V of soln. in liters
M acetone
Transcribed Image Text:up the 1. In a reaction involving the iodination of acetone, the following volumes were used to make reaction mixture: 10 mL 4.0 M acetone + 10mL 1.0 M HCl + 10 mL 0.0050 M 1₂ + 20 mL H₂O a. How many moles of acetone were in the reaction mixture? Recall that, for a component A, no. moles A = MA X V, where MA is the molarity of A and V is the volume in liters of the solution of A that was used. b. What was the molarity of acetone in the reaction mixture? The volume of the mixture was 50 mL, 0.050 L, and the number of moles of acetone was found in Part a. Again, MA = moles acetone no. moles A V of soln. in liters M acetone
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