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1. Propose a mechanism and predict the product.
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Solved in 2 steps with 1 images
- Hey, stuck on this sheet :)) (no explanation/diagram needed)C6H8O6(aq) + C12H7O2NCL2(aq) ----> C6H6O6(aq) + C12H9O2NCL2(aq) - C12H7O2NCL2 is abbreviated as DCIP - Molar Lass of C6H8O6(s) is 176.14 g/mol - Daily recommended intake (DRI) for adults: 90 mg of Vitamin C Askor & Bich found that it required 23.14 mlof 1.32 x 10^-3 M DCIP soliution to reach the endpoint when titrating a 7.50ml aliquot of pear juice. How many mg of ascorbic acid, C6H8O6 are present in the juice aliquot? _5.38_____(can you please show how to calculate this answer) How many ml of this juice would Bich have to drink in order to meet the daily recommended intake (DRI)?__126__ (Which diagram is the correct one? What other procedure can be used to solve this problem? write down ways to solve. first, execute plan 1 to solve the problem. Please explain every step. Think about the way that you can use to make sure that your answer makes sense. write down your assessment.
- 2. What is (A) and (B)?Oceanic uptake of carbon dioxide is thus described:CO2 (g) + H2O ⇔ H2CO3, K = [H2CO3]/PCO2 = 3 x 10-2 M atm-1 H2CO3 ⇔ HCO3- + H+, K = [HCO3-][H+]/[H2CO3] = 9 x 10-7 moles/LHCO3- ⇔ CO32 - + H+, K = [CO32 -][H+]/[HCO3-] = 7 x 10-10 moles/L CaCO3 ⇔ Ca2+ + CO32- Kc = 4 x 10-9 M2 What is the full charge balance equation for this system?Three white wine brands, D, M, and B were tested for tartaric acid (FW=150.09) content. Tartaric acid has two acidic hydrogens. The allowable tartaric acid content in wine is in between 0.5 g to 10 g per liter. The wine is considered to be unstable with too much tartaric acid and content. However, since the bottle storing NaOH was left ajar for over two weeks, this was standardized again with KHP (FW=204.22) thrice with the following masses of KHP and their respective volumes, shown in the table 1. Table 1. Trial 1 Trial 2 Trial 3 W (KHP), mg 200.0 198.5 187.6 V (NaOH), mL 20.00 18.20 19.40 C (NaOH), M ? ? ? Preparation of the wine sample: 50.00 mL of each wine (d=1.75 g/mL) was diluted to 250.0 mL with water and a 50.00 mL aliquot was titrated with the NaOH, with results in table 2. Table 2. D M B V (NaOH), mL 20.00 18.20 19.40 W (Tartaric acid), mg ? ? ? Answer the following: In which trial…