1. P(A U B)= В A 2. value of F= C 3 value of D= 4. value of C= F 5. value of E= GIVEN: P(A)= .45 P(B)= .35 P(A N B)= .20
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- Independent surveys show that the average IQ of 9 r/s babies exposed to cocaine in the uterus is 81 with s.d. 18, while the average IQ of 20 r/s babies unexposed to cocaine in the uterus is 99 with s.d. 9. Construct a 90% c.i. for the difference between the overall average IQs of exposed and unexposed babies. Assume that both populations are normal.Suppose the relationship between Y and X is given by: Y = 1million + 56.43*X + error By how much does the expected value of Y change if X increases by 23.09 units? (Round your answer to two decimal places: ex: 123.45)Researchers wanted to determine whether fence lizards learned to avoid fire ants. To determine this, they gathered lizards from eastern Arkansas (where there were no fire ants), and from southern Alabama (which had been invaded by fire ants). The lizards were then exposed to fire ants, and researchers measured how long (in seconds) it took the lizards to flee. Suppose that mu_I is the average time to flee for a lizard that lives in the invaded areas in Alabama, and mu_U is the average time to flee for a lizard living in the uninvaded areas of Arkansas. When the data is loaded into the correct tool in StatKey, and the "Generate 1000 samples" button is clicked, here is what StatKey generates:- see image. The researchers observed that the lizards from Alabama had an average response time of 32 seconds, and the lizards from Arkansas had an average response time of 44 seconds. Using this, which of the following is closest to the P-value for this hypothesis test? What conclusions can we make…
- Researchers wanted to determine whether fence lizards learned to avoid fire ants. To determine this, they gathered lizards from eastern Arkansas (where there were no fire ants), and from southern Alabama (which had been invaded by fire ants). The lizards were then exposed to fire ants, and researchers measured how long (in seconds) it took the lizards to flee. Suppose that mu_I is the average time to flee for a lizard that lives in the invaded areas in Alabama, and mu_U is the average time to flee for a lizard living in the uninvaded areas of Arkansas. The researchers are interested in understanding if lizards from invaded areas are faster to flee when exposed to ants. What should they use for their hypotheses? H0:μI−μU= HA:μI−μU What are the hypothesis and null hypothesis answers? And how did you get the hypothesis and null hypothesis without any numbers?n e e d H e l PAnna wants to estimate the average shower time of teenagers. From the sample of 50 teenagers, she found out that it takes 5 minutes for teenagers to shower. What is the parameter? a. sample of 50 teenagers b. 50 teenagers in 5 minutes c. average shower time of teenagers d. took 5 minutes for teenagers to shower
- How would you figure out b,c & e?In recent years, a substantial amount of research has focused on a possible relationship between chemical contamination of various sorts and mental impairment in children. An article reported data on hair-lead concentration for a sample of mentally impaired children for which the cause of impairment was unknown. Sample statistics were n = 41 X Bar = 16 ppm s = 5.36 ppm The paper states that 14.27 ppm is considered the acceptable upper limit of hair-lead concentration. Let μ= the average hair-lead concentration for all mentally impaired children with the cause of impairment unknown. H0: μ = 14.27 versus H1: μ > 14.27 at 0.01 significance level Does the given sample data support the research hypothesis that true average hair concentration for all such mentally impaired children exceeds the acceptable upper limit? Assume normality. 1. reject null hypothesis 2. fail to reject null hypothesisPeople having Raynauds syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experiment to study the extent of this impairment, each subject immersed a forefinger in water and the resulting heat output (cal/cm2/min) was measured. For m = 12 subjects with the syndrome, the average heat output was x = 0.64, and for n = 12 non-sufferers, the average output was 2.05. Let µ1 and µ2 denote the true average heat outputs for the two types of subjects. Assume that the two distributions of heat output are normal with σ1 = 0.2 and σ2 = 0.2. 1) Consider testing H0: µ1 − µ2 = 0 versus Ha: µ1 − µ2 < 0 at level 0.01. Describe in words what Ha says, and then carry out the test. 2) What is the probability of a type II error when the actual difference between µ1 and µ2 is µ1 − µ2 = −1.2? 3) Assuming that m=n, what sample sizes are required to ensure that β=0.1when µ1− µ2 = −1.2?