1. Point R is on line segment QS. Given QS = 2x+2, QR 3x- 5, and RS = 5x - 5, determine the numerical length of QR.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.5: Iterative Methods For Solving Linear Systems
Problem 20EQ
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Tmeme
Transition
4
6 E
8.
1.
Point R is on line segment QS. Given QS = 2x +2, QR = 3x- 5, and
RS = 5x-5, determine the numerical length of QR.
%3D
Enter work below (double click). All steps must be shown to receive full credit.
Rhiannon's work:
Jonathan's work:
QR+RS=QS
3x-5 +5x-5%32x+2
Jack's work:
Milleena's work:
QR+RS=QS
QS=QR+QS
2x+2=3x-5+5x-5
QR+RS=QS
3x-5+5x-5%3D2X+2
3x-5+5x-5%3D2X+2
8x-10=2x+2
6x-10=2
2x+238x-10
8x-10=2x+2
8x-10=2x+2
2x+12=8x
6x-10-2
-10=-6x+2
6x divided by 12
6x/6=12/6
-12/-6x=-6x/-6x
6x/6=12/6
x-2
x=2
x=2
x=2
QR=3x-5
6-5
qr=3x-5
qr=6-5
qr=1
QR = 3x-5
QR=3x-5
QR=6-5
QR=1
Final Answer
6-5
QR= 1
QR=1
QR=1
Transcribed Image Text:ayout Tmeme Transition 4 6 E 8. 1. Point R is on line segment QS. Given QS = 2x +2, QR = 3x- 5, and RS = 5x-5, determine the numerical length of QR. %3D Enter work below (double click). All steps must be shown to receive full credit. Rhiannon's work: Jonathan's work: QR+RS=QS 3x-5 +5x-5%32x+2 Jack's work: Milleena's work: QR+RS=QS QS=QR+QS 2x+2=3x-5+5x-5 QR+RS=QS 3x-5+5x-5%3D2X+2 3x-5+5x-5%3D2X+2 8x-10=2x+2 6x-10=2 2x+238x-10 8x-10=2x+2 8x-10=2x+2 2x+12=8x 6x-10-2 -10=-6x+2 6x divided by 12 6x/6=12/6 -12/-6x=-6x/-6x 6x/6=12/6 x-2 x=2 x=2 x=2 QR=3x-5 6-5 qr=3x-5 qr=6-5 qr=1 QR = 3x-5 QR=3x-5 QR=6-5 QR=1 Final Answer 6-5 QR= 1 QR=1 QR=1
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