1. Solve by Euler's method and by classical 4th-order RK method: dy₁ = 2y₁ - 4y2, dx dy₂ = y₁ - 3y₂ dx with the initial values y₁ (0) = 3, y₂ (0) = 0 using a step size h = 0.1 from x = 0 to 1.

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A: ∫ydyy+2 Substitute, u+5=y+2 Then , du=12y+2dy ⇒2y+2 du =dy ⇒2u+5 du =dy and y=u+52-2=u2+10u+23

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