1. The apparent power of a load is 4300 VA with lagging power factor of 0.875. The magnitude of the rms voltage across the load is given by [Vms| = 795 V. Assume f=60 Hz. Find the (a) average power of the load. (b) reactive power of the load. (c) complex power of the load.
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- the average power of a load is 3.37 kW with a leading power factor of 0.835. the magnitude of the rms voltage accross the load is given by |Vrms| = 450 V. If the frequency is assumed to be 60 Hz, calculate the apparent power, reactive power, impendance and the value of the capacitor in the circuit.A motor connected to a 220-V supply line from the power company has a current of 7.6 A. Both the current and the voltage are rms values. The average power delivered to the motor is 1317 W. (a) Find the apparent power, the reactive power, and the power factor when ω=377 rad/s. (b) Find the capacitance of a parallel capacitor that will result in a unity power factor of the combination. (c) Find the current in the utility lines after the capacitor is installed.five infinite-impedance volunteers,calibrated to read rms values,are connected as shown below. let R= 200, L=0.400H,C=6.0 Mf, and V=30.0 v. what's the reading of the voltmeter's V1,V2,V3,V4 and V5 if W= 200 rad/s
- An audio power amplifier delivers a 30 volt RMS 1 kHz sine to a loudspeaker. If the loudspeaker impedance at this frequency is 7 at 45°, determine the RMS current delivered to the load and the true power.The values of the parameters in the circuit shown are L1=8 mH; L2=2 mH; k=0.75; Rg=1 Ω; and RL=7 Ω. Ifvg=542 cos 1000t V, find 1. a) the rms magnitude of vo;2. b) the average power delivered to RL;3. c) the percentage of the average power generated by the idealvoltage source that is delivered to RL.A supply voltage v given by v = (240 sin 314t + 40 sin 942t + 30 sin 1570t) volts is applied to a circuit comprising a resistance of 12 ohmconnected in series with a coil of inductance 9.55 mH. Determine (a) an expression to represent the instantaneous value of the current, (b) the rms voltage, (c) the rms current, (d) the power dissipated, and (e) the overall power factor.
- Communication Systems Consider the signal w(t) = 6cos(8pt) + 2cos(4pt) Calculate the rms value Wrms and the normalized average power Pw of the signal. Find and plot the power spectral density Pw (f ) of the signal. Find the autocorrelation function of w(t) [Hint: 2cos x cos y = cos(x + y) + cos(x - y) ; 2cos2 x = (1+ cos 2x) ]The rms output voltage of an AC source is 150 V and the operating frequency is 90 Hz. Which of the following equation gives the output voltage as a function of time? a. (150 ?) sin(283?)b. (150 ?) sin(565?)c. (212 ?) sin(283?)d. (212 ?) sin(565?)An example power system has two distinct manufacturing areas, one with harmonic loads, and another with only linear loads. The portion of the system with the harmonic loads draws 75 A rms at 60 Hz, 10 A rms at 300 Hz, and 5 A rms at 420 Hz. The part of the system with only linear loads draws 75 A rms at 60 Hz. (i) What is the total load current (at 60 Hz) if both manufacturing plants are running? Calculate the THD. (ii) What is the total load current (at 60 Hz) if only the manufacturing plant with harmonic loads is running? Calculate the THD.
- The voltage and current at the terminals of a network are v = 15+400 cos 500t+100 sin 1500t V, i = 2+5 sin (500t+ 60 ∘)+3 sin (1500t− 15 ∘ ) A. The current is in the direction of the voltage drop across the terminals. What is the rms value of the current?Help me please IN THE CIRCUIT SHOWN, THE VALUE OF THE CURRENT SOURCE IS IN RMS VALUE. DETERMINE: A) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE INDUCTOR TERMINALS, VL B) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE RESISTOR TERMINALS, VR C) THE AVERAGE POWER ABSORBED BY THE 40 Ω RESISTORA sinusoidal voltage is given by the expression v=300 cos(120πt+30∘) V.1. What is the period of the voltage in milliseconds?2. What is the frequency in hertz?3. What is the magnitude of v at t=2.778 ms?4. What is the rms value of v?