1. The circuit shown below is a dc model of a residential power distribution circuit. Use the mesh-current method to find the branch currents /₁ - 16. 1Ω 125 V 125 V + Ans. i = 23.76 A i2 = 5.33 A ig 2 Ω = 18.43 Aig 1Ω ww i=15 A i5 = 9.77 A = 8.66 A – i 6Ω is Σ12Ω 16 324 Ω

1. The circuit shown below is a dc model of a residential power distribution circuit. Use the mesh-current method to find the branch currents /₁ - 16. 1Ω 125 V 125 V + Ans. i = 23.76 A i2 = 5.33 A ig 2 Ω = 18.43 Aig 1Ω ww i=15 A i5 = 9.77 A = 8.66 A – i 6Ω is Σ12Ω 16 324 Ω

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.25P: Consider the series RLC circuit of Problem 2.7 and calculate the complex power absorbed by each of...

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Question

1. The circuit shown below is a dc model of a residential power distribution circuit. Use the
mesh-current method to find the branch currents /₁ - 16.
1Ω
125 V
125 V
+
Ans.
i = 23.76 A
i2 = 5.33 A
ig
2 Ω
= 18.43 Aig
1Ω
ww
i=15 A
i5 = 9.77 A
= 8.66 A
–
i 6Ω
is Σ12Ω
16
324 Ω

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