1. Two solid shafts of different materials are rigidly fastened together and attached to rigid supports as shown. The aluminum segment is 3 inches in diameter and G = 4 x 10^6 psi. The steel segment has a diameter of 2 inches and G = 12 x 10^6 psi. The torque, T = 10 kips.in. is applied at the junction of the two segments. Compute the maximum shearing stress developed in the assembly.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Q1 With fbd.
1. Two solid shafts of different materials.
are rigidly fastened together and
attached to rigid supports as shown. The
aluminum segment is 3 inches in
diameter and G = 4 x 10^6 psi. The steel
segment has a diameter of 2 inches and G
12 x 10^6 psi. The torque, T = 10
kips.in. is applied at the junction of the
two segments. Compute the maximum
shearing stress developed in the
=
assembly.
3 ft
6 ft
CT st
Steel.
Tal
T = 10 kip in.
2 in. dia.
G₁ = 12 x 106 psi
st
Aluminum
3 in. dia.
Gal
= 4 x 106 psi
Transcribed Image Text:1. Two solid shafts of different materials. are rigidly fastened together and attached to rigid supports as shown. The aluminum segment is 3 inches in diameter and G = 4 x 10^6 psi. The steel segment has a diameter of 2 inches and G 12 x 10^6 psi. The torque, T = 10 kips.in. is applied at the junction of the two segments. Compute the maximum shearing stress developed in the = assembly. 3 ft 6 ft CT st Steel. Tal T = 10 kip in. 2 in. dia. G₁ = 12 x 106 psi st Aluminum 3 in. dia. Gal = 4 x 106 psi
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