1. What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure? 2. If the current through the top branch is I2 = 0.41 A, what is the current through the bottom, I3, in amps?

1. What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure? 2. If the current through the top branch is I2 = 0.41 A, what is the current through the bottom, I3, in amps?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter19: Electric Potential And Electric Field

Section: Chapter Questions

Problem 6PE: Integrated Concepts (a) What is the average power output of a heart defibrillator that dissipates...

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Question

1. What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure?

2. If the current through the top branch is I₂ = 0.41 A, what is the current through the bottom, I₃, in amps?

E1 = 18 V
0.5 2
R
2.5 0
R
a
e
R
.1.5 2
0.5 2
E2 = 45 V

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