1. What must be the pull in a L(10) meters tape in order to remove correction, given the following? a = M x10“ m² Weight of tape, 11 N E= 2x10" N/m² Po = G kg The tape lenoth is supported at both ends

Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter14: Sheet-pile Walls
Section: Chapter Questions
Problem 14.9P
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Equivalents
G = 6
M = 4
L = 8

1. What must be the pull in a L(10) meters tape in order to remove the sag
correction, given the following?
a = M x10“ m?
E = 2x10" N/m?
Po = G kg
Weight of tape, 11 N
The tape length is supported at both ends.
Transcribed Image Text:1. What must be the pull in a L(10) meters tape in order to remove the sag correction, given the following? a = M x10“ m? E = 2x10" N/m? Po = G kg Weight of tape, 11 N The tape length is supported at both ends.
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