1. What will be the product(s) of the following reaction? NH2 H2N NaNH2 -NH2 liquid NH3 -NH2 II IV (A) I only (B) I and II (C) I and III (D) I and IV
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- select the expected major organic product. I II III IV VPredict the product C of the following reaction below and briefly explain youranswer.[PtCl3(C2H4)]¯ + NH3 → CArrange the alkyl halides in order of increasing reactivity in an SN2 reaction with KI in acetone (least first). I, IV, III, II II, III, I, IV IV, I, III, II III, II, IV, I
- What starting materials are needed to prepare the compound below by intramolecular Michaelreaction?(b) Predict the suitable solvent (H2O or CH3COCH3) to increase the reaction of bromopropane(CH3CH2CH2Br) with sodium hydroxide (NaOH). Two reactions are shown below:Arrange the following compounds in order of increasing reactivity to nucleophilic addition.I. Pentan-2-one II. Pentanal III. 3-methybutan-2-one A. III, II, I B. I, II, III C. II, I, III D. III, I, II
- Which is more acidity; 4-nitrobutanol or 2-nitrobutanol and how?4 Part 3. Give the IUPAC names of the following compoundsPart 5: Predict the products, if any, of the following reactions.Below is a schematic representation of possible reaction that compound X can undergo.Use the scheme to answer the following questions. A.What is the IUPAC name for compound X B. What type of reactions is/are represented by (i) and(ii). C.Compound X undergo transitions through either (A) or (B) to produce compounds (1),(2),(3) and (4). Draw the structure of (A) and (B).
- How to prepare the Organometallic Reagents ?Tunicates are marine animals that are called "sea squirts" because when they are taken out of water, they tend to contract and expel seawater. Lepadiformine is a cytotoxic agent (toxic to cells) isolated from a marine tunicate. During a recent synthesis of lepadiformine, the investigators observed the formation of an interesting by-product (3) while treating diol 1 with a reagent similar in function to PBr3 (J. Org. Chem. 2012, 77, 3390–3400):The reaction H2C=CHCH2Br + NaN3 followed by reaction with LiAlH4 yields CH3CH2CH2NH2 H2C=CHCH2NH2 H2C=CHCH2N3 none of the above