1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is the kinetic energy of the ball? Assume the ball is a uniform, solid sphere. 2 k={/m² ² + 1 ² ] = ³/2mr ² 1=²..15.037 = .00222 k=15-48² +00222-421 = 172.8+1.958 = 174.758 J r=1.2 2-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with a constant angular acceleration 2.7 rad/s². 2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s? 2.7-t=5.7 (t= 2.11s 3. What is the linear velocity of the tip of the propeller at 5.7 rad/s? v=rw 1.2-5.7= (6.84 m/s 4. What is the tangential acceleration of the tip of the propeller at this time? 1.2.2.7 = (3.24/2 a=ra 5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time? 2 9₁== 6.84/1.238.988N 6. Consider a particle of mass m = 22.0 kg revolving around an axis with a constant angular velocity of 6.00 rad/s. The perpendicular distance from the particle to the axis is r=0.750 m. What is the kinetic energy of the particle? 2
1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is the kinetic energy of the ball? Assume the ball is a uniform, solid sphere. 2 k={/m² ² + 1 ² ] = ³/2mr ² 1=²..15.037 = .00222 k=15-48² +00222-421 = 172.8+1.958 = 174.758 J r=1.2 2-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with a constant angular acceleration 2.7 rad/s². 2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s? 2.7-t=5.7 (t= 2.11s 3. What is the linear velocity of the tip of the propeller at 5.7 rad/s? v=rw 1.2-5.7= (6.84 m/s 4. What is the tangential acceleration of the tip of the propeller at this time? 1.2.2.7 = (3.24/2 a=ra 5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time? 2 9₁== 6.84/1.238.988N 6. Consider a particle of mass m = 22.0 kg revolving around an axis with a constant angular velocity of 6.00 rad/s. The perpendicular distance from the particle to the axis is r=0.750 m. What is the kinetic energy of the particle? 2
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 53P
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