1.19 A; C=C double bond length in alkenes = 1.35 Å; C-C single bond length: %3!

Chemistry: The Molecular Science
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Publisher:John W. Moore, Conrad L. Stanitski
Chapter20: Chemistry Of Selected Transition Elements And Coordination Compounds
Section: Chapter Questions
Problem 105QRT
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c. Consider the two Pt complexes shown below. Discuss the oxidation states of the two Pt centers along
with the bonding details between the alkyne ligands and the Pt center. What is the charge and bond order
for the "triple-bond" in the alkyne ligand for each complex? Some useful information: C=C triple bond
length in a free alkyne = 1.19 Å; C=C double bond length in alkenes = 1.35 Å; C-C single bond length =
1.54 Å.
Complex A
CH3
Ph2MeP-
Pt
-PMePh2
H3C
CH3
Pt-CH, = 2.10 A
Pt-PR, = 2.29 Á
Pt-alkyne = 2.28 A
C=C = 1,22 A
Me-C=C = 164°
Alkyne C=C carbons are perpendicular
to the square plane of the complex (Pt,
P, & CH3 atoms)
Complex B
Ph3P
PPH3
CI
Pt-PR3 = 2.28 A
Pt-alkyne = 2.05 Á
C=C = 1.38 Â
Me-C=C = 134°
Alkyne carbons are in the square
plane of the complex
Transcribed Image Text:c. Consider the two Pt complexes shown below. Discuss the oxidation states of the two Pt centers along with the bonding details between the alkyne ligands and the Pt center. What is the charge and bond order for the "triple-bond" in the alkyne ligand for each complex? Some useful information: C=C triple bond length in a free alkyne = 1.19 Å; C=C double bond length in alkenes = 1.35 Å; C-C single bond length = 1.54 Å. Complex A CH3 Ph2MeP- Pt -PMePh2 H3C CH3 Pt-CH, = 2.10 A Pt-PR, = 2.29 Á Pt-alkyne = 2.28 A C=C = 1,22 A Me-C=C = 164° Alkyne C=C carbons are perpendicular to the square plane of the complex (Pt, P, & CH3 atoms) Complex B Ph3P PPH3 CI Pt-PR3 = 2.28 A Pt-alkyne = 2.05 Á C=C = 1.38 Â Me-C=C = 134° Alkyne carbons are in the square plane of the complex
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