1.602x 10-19 C. m= 9.11x 10-81 kg h = 6.625x 10*-34 J.s, c= 3x 10*8 m/s, 8.85x10-12 F/m k=1.38x10*-23J/K. Avogadros number= 6.023x10 26, kT= 0.0259 eV (et T=300K) Determine the probabilty of state being occupied by an electron at (EF-0.04), assume T- 300 K 23% O 10% O 17.5% O 15.5% O

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Chapter32: Medical Applications Of Nuclear Physics
Section: Chapter Questions
Problem 34PE: How many kilograms of water are needed to obtain the 198.8 mol of deuterium, assuming that deuterium...
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1.602x 10*-1 C,
m= 9.11x 10-81 kg,
h=6.626x 10^-34 J.s,
o=D3x 10'8 m/s,
8.85x10-12 F/m
k-1.38x10*-23/K, Avogadro's number= 6.023x10 26, kT = 0.0259 ev (et T=300K)
Determine the probability of state being occupied by an electron at
(EF-0.04), assume T- 300K
23% O
10% O
17.5%
15.5% O
In a parallel-plate diode. the anoce is at 240V with rescect to the cathode
Transcribed Image Text:estions 1.602x 10*-1 C, m= 9.11x 10-81 kg, h=6.626x 10^-34 J.s, o=D3x 10'8 m/s, 8.85x10-12 F/m k-1.38x10*-23/K, Avogadro's number= 6.023x10 26, kT = 0.0259 ev (et T=300K) Determine the probability of state being occupied by an electron at (EF-0.04), assume T- 300K 23% O 10% O 17.5% 15.5% O In a parallel-plate diode. the anoce is at 240V with rescect to the cathode
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