10) A mass m2 hangs from the end of a rope which passes over a disk shaped pulley of mass M and radius R. On the other end, the rope is attached to a mass m: which is free to slide on a frictionless surface. m1 a) Find the acceleration of the system. b) Find the tension or tensions m2 g m; +m,+M/2 in the rope. (a: a=- , b: not given) m2

10) A mass m2 hangs from the end of a rope which passes over a disk shaped pulley of mass M and radius R. On the other end, the rope is attached to a mass m: which is free to slide on a frictionless surface. m1 a) Find the acceleration of the system. b) Find the tension or tensions m2 g m; +m,+M/2 in the rope. (a: a=- , b: not given) m2

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section: Chapter Questions

Problem 80A

See similar textbooks

Similar questions

A model airplane with mass 0.750 kg is tethered by awire so that it flies in a circle 30.0m in radius. The airplaneengine provides a net thrust of 0.800N perpendicular to thetethering wire. (a) Find the torgue the net thrust produces aboutthe centre of the circle. (b) Find the angular acceleration of theairplane when it is in level flight. (c) Find the translationalacceleration of the airplane, and the tangent to its flightpath.
A 1,300 kg car is capable of making a turn at a maximum speed of 15 m/s without spinning out. If the coefficient of friction between the car's tires and the road is 0.6, find the radius of this turn. Radius_____ m (round to the nearest whole number)
One end of a cord is fixed and a small 0.550-kg object is attached to the other end, where it swings in a section of a vertical circle of radius 1.50 m, as shown in the figure below. When ? = 17.0°, the speed of the object is 6.00 m/s. At this instant, find the total acceleration and degree below the cord.
A car of mass m travels around a flat, circular curve of radius r at the fastest possible speed, v = 13.8 m/s without sliding off. The car and road have a coefficient of friction, μ between them. If the car wishes to take the turn at 2.3x the velocity, by what factor would the radius need to increase (so the car doesn't slide off) ? Give your answer to 1 decimal place.
Because of Earth’s rotation about its axis, you weigh slightlyless at the equator than at the poles. Explain.
a car has a constant acceleration , start from rest untill vf=22 m/s in 9 s , if the tire radius is 58 cm , calculate : a) The number of possible turns of the wheels during normal vehicle movement assuming no slip . b) the speed of wheels turn in ( rev/s )
A model airplane with mass 0.750 kg is tethered by a wire sothat it flies in a circle 30.0 m in radius. The airplane engineprovides a net thrust of 0.800 N perpendicular to the tetheringwire. (a) Find the torque the net thrust produces aboutthe center of the circle. (b) Find the angular acceleration ofthe airplane when it is in level flight. (c) Find the linear accelerationof the airplane tangent to its flight path.
A scientist claims that people who compete in the Olympic event of skeleton are insane. With their chin often 3 in. from the ice, they rush down the track at speeds of 75 mph on a nearly weightless sled. One turn in the Sochi Olympics had a radius of 50 m. At a speed of 75 mph, calculate the total force on a 145-lb rider. Round the final answer to the nearest whole number.
Discuss the physics involved in the spin cycle of a washing machine. In particular, how is circular motion related to the removalof water from the clothes?
A blood is placed centrifuge of radius 17.0 The mass of a red blood cell 3.0*10^ -16 kg. and the magnitude of the force acting on it as it settles out of 4.0 * 10 ^ - 11 .many revolutions per second should the centrifuge operated?
When you take your 1900-kg car out for a spin, you go arounda corner of radius 53 m with a speed of 13 m>s. The coefficient ofstatic friction between the car and the road is 0.88. Assuming yourcar doesn’t skid, what is the force exerted on it by static friction?
One way to provide artificial gravity (i.e., a feeling of weight) on long space voyages is to separate a spacecraft into two parts at the ends of a long cable, and set them rotating about their center of mass. A craft has been separated into two parts with a mass of 79500 kg each, at the ends of a cable with their centers of mass 54 m apart, rotating around the center point of the cable with a period of 173.2 seconds. If the cable is reeled in so that the the centers of the two pieces are now only 41.58 m apart, what will be the new period? the answer I have been getting has been because I have been using Tf= (rfTi)/ri which was found by using the conservation of angular momentum(inital angular momentum equals final). What have I been doing wrong?