9) How many grams of KNO3 are required to make 100.0 mL of a 0.531 M KNO3 solution? (Answer:5.37 g KNO3)Volume of soIution (V) = 100.0OML= 0.100LUnifs of mojanty= mol /L%3DMolanty of soluhon(M)=0.531H= 0.531 mol/LNu -Wn= moles of soIule = mass/molar mass Molar mass of KNO3= 101.1 glmolMass of KN03=V = Volume oF SOluion in litresH= (mass/ molar mass) (1/v)Mass = M molar mass VMass-o. 531 mol/L 101. 1g/mol 0. 100 LM= (mass/molar mass) × (1/V)Mass = 5.37D.10) How many milliliters of the solution prepared in the question above would be required to make250.0 mL of a 0.1000 M KNO3 solution? (Answer: 47.1 mL)

Number of moles of solute p resent in 1 litre of solution is called molarity (M) i.e M = n /V (in…

Answered: 10) How many millilit 250.0 mL of a 0.1

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10) How many millilit 250.0 mL of a 0.1

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.40P: 6-40 What is the molarity of each solution? (a) 47 g of KCI dissolved in enough water to give 375 mL...

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

9) How many grams of KNO3 are required to make 100.0 mL of a 0.531 M KNO3 solution? (Answer:
5.37 g KNO3)
Volume of soIution (V) = 100.0OML= 0.100L
Unifs of mojanty= mol /L
%3D
Molanty of soluhon(M)=0.531H= 0.531 mol/L
Nu -W
n= moles of soIule = mass/molar mass Molar mass of KNO3= 101.1 glmol
Mass of KN03=
V = Volume oF SOluion in litres
H= (mass/ molar mass) (1/v)
Mass = M molar mass V
Mass-o. 531 mol/L 101. 1g/mol 0. 100 L
M= (mass/molar mass) × (1/V)
Mass = 5.37D.
10) How many milliliters of the solution prepared in the question above would be required to make
250.0 mL of a 0.1000 M KNO3 solution? (Answer: 47.1 mL)

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