- 10 nC 40 nC 3 ст F, 2 сm 1 cm 1 nC 0.1 nC Figure 2: (1)The force on the 0.1nC charge due to the other three charges shown in the figure 2 is: F = (-4.88696 × 10-5i – 1.57201 x 10-53)N (True,False) (ii) The magnitude and the direction of the net force on the 0.1nC charge due to the other three charges shown in the figure 2. is: F = 5.13358 x 10-$N and 0 = 197.8317° (True,False)

- 10 nC 40 nC 3 ст F, 2 сm 1 cm 1 nC 0.1 nC Figure 2: (1)The force on the 0.1nC charge due to the other three charges shown in the figure 2 is: F = (-4.88696 × 10-5i – 1.57201 x 10-53)N (True,False) (ii) The magnitude and the direction of the net force on the 0.1nC charge due to the other three charges shown in the figure 2. is: F = 5.13358 x 10-$N and 0 = 197.8317° (True,False)

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Electric Fields

Section: Chapter Questions

Problem 23.37P: A rod 14.0 cm long is uniformly charged and has a total charge of 22.0C. Determine (a) the magnitude...

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Similar questions

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