10. 1/3 points | Previous Answers SerCP11 16.2.P015.M. My Notes Ask Your Teacher Two point charges 1+6.00 nC and 21.80 nC are separated by 45.0 cm (a) What is the electric potential at a point midway between the charges? (b) What is the potential energy of the pair of charges? What is the significance of the algebraic sign of your answer? Positive work must be done to separate the charges Negative work must be done to separate the charges.

Given two particles with 2.00-C charges as shown in Figure P25.19 and a particle with charge q = 1.28 10-18 C at the origin, (a) what is the net force exerted by the two 2.00-C; charges on the charge q? (b) What is the electric field at the origin due to the two 2.00-C particles? (c) What is the electric potential at the origin due to the two 2.00-C particles?

The three charged particles in Figure P20.11 are at the vertices of an isosceles triangle (where d = 2.00 cm). Taking q = 7.00 C, calculate the electric potential at point A, the midpoint of the base. Figure P20.11

Three particles with equal positive charges q are at the corners of an equilateral triangle of side a as shown in Figure P20.10. (a) At what point, if any, in the plane of the particles is the electric potential zero? (b) What is the electric potential at the position of one of the particles due to the other two particles in the triangle? Figure P20.10

A uniformly charged filament lies along the x axis between x = a = 1.00 m and x = a + = 3.00 m as shown in Figure P25.66. The total charge on the filament is 1.60 nC. Calculate successive approximations for the electric potential at the origin by modeling the filament as (a) a single charged particle at x = 2.00 m, (b) two 0.800-nC charged particles at x = 1.5 m and x = 2.5 m, and (c) four 0.400-nC charged particles at x = 1.25 m, x = 1.75 m, x = 2.25 m, and x = 2.75 m. (d) Explain how the results compare with the potential given by the exact expression v=klQlln(l+aa)

A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm. carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?

A uniformly charged insulating rod of length 14.0 cm is bent into the shape of a semicircle as shown in Figure P25.44. The rod has a total charge of 7.50 C. Find the electric potential at O, the center of the semicircle.

(a) Find the electric potential, taking zero at infinity, at the upper right corner (the corner without a charge) of the rectangle in Figure P16.13. (b) Repeat if the 2.00-C charge is replaced with a charge of 2.00 C. Figure P16.13 Problems 13 and 14.

A particle with charge -40.0 nC is on the x axis at the point with coordinate x = 0. A second panicle, with charge -20.0 nC, is on the x axis at x = 0.500 in. (i) Is the point at a finite distance where the electric field is zero (a) to the left of .v = 0, (b) between x = 0 and x = 0.500 in, or (c) to the right of x m 0.500 in? (ii) Is the electric potential zero at this point? (a) No; it is positive, (b) Yes. (c) No; it is negative. (iii) Is there a point at a finite distance where the electric potential is zero? (a) Yes; it is to the left of x = 0. (b) Yes; it is between x = 0 and x = 0.500 in. (c) Yes; it is to the right of x = 0.500 in. (d) No.

An infinite number of charges with q = 2.0 C are placed along the x axis at x = 1.0 m, x = 2.0 m, x = 4.0 m, x = 8.0 m, and so on, as shown in Figure P26.78. Determine the electric potential at the point x = 0 due to this set of charges. Hint: Use the mathematical formula for a geometric series, 1+r+r2+r3+r4+=11r FIGURE P26.78