10. A thermodynamic cycle using water is shown on the T-s diagram of Figure 7.26. Calculate thecoefficient of performance for this cycle using the equationh, – h,COP =(h, – he) – (h, – hɔ)State AState BState CState DX = 1.00P = 300. psiaX = 0.00Po = 10.0 psiaP = 10.0 psiaThe processes areA → B = isentropic compression,B → C = isobaric expansion,C →D= isentropic expansion,D - A = isothermal compression.FIGURE 7.26

It is required to determine COP of given cycle

10. A thermodynamic cycle using water is shown on the 7-s diagram of Figure 7.26. Calculate the coefficient of performance for this cycle using the equation h, – h, COP = (h – he) – (h, – hɔ) State A State B State C State D X = 1.00 P, = 10.0 psia P = 300. psia Xc = 0.00 Pp = 10.0 psia The processes are A - B = isentropic compression, B -C = isobaric expansion, C→D = isentropic expansion, D - A = isothermal compression. FIGURE 7.26

10. A thermodynamic cycle using water is shown on the 7-s diagram of Figure 7.26. Calculate the coefficient of performance for this cycle using the equation h, – h, COP = (h – he) – (h, – hɔ) State A State B State C State D X = 1.00 P, = 10.0 psia P = 300. psia Xc = 0.00 Pp = 10.0 psia The processes are A - B = isentropic compression, B -C = isobaric expansion, C→D = isentropic expansion, D - A = isothermal compression. FIGURE 7.26

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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