10.0 g of acetic acid (CH3COOH) reacts with 10.0 g of lead(II) hydroxide to form water and lead (II) acetate (Pb(CH3coo)2). a) What is the balanced chemical equation? b) Which reactant is in excess?

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Author:Lawrence S. Brown, Tom Holme
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Chapter4: Stoichiometry
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Problem 4.8PAE: 4.8 In an experiment carried out at very low pressure, 13x1015 molecules of H2 are reacted with...
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10.0 g of acetic acid (CH3COOH) reacts with 10.0 g of lead(II) hydroxide to form water and lead (II)
acetate (Pb(CH3coo)2).
a) What is the balanced chemical equation?
b) Which reactant is in excess?
Transcribed Image Text:10.0 g of acetic acid (CH3COOH) reacts with 10.0 g of lead(II) hydroxide to form water and lead (II) acetate (Pb(CH3coo)2). a) What is the balanced chemical equation? b) Which reactant is in excess?
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