   # The compound SF 6 is made by burning sulfur in an atmosphere of fluorine. The balanced equation is Sa(s) + 24 F 2 (g) → SF 6 (g) Starting with a mixture of 1.6 mol of sulfur. Sg, and 35 mol of F 2 , (a) Which is the limiting reagent? (b) What amount of SF 6 is produced? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 13PS
Textbook Problem
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## The compound SF6 is made by burning sulfur in an atmosphere of fluorine. The balanced equation isSa(s) + 24 F2(g) → SF6(g)Starting with a mixture of 1.6 mol of sulfur. Sg, and 35 mol of F2, (a) Which is the limiting reagent? (b) What amount of SF6 is produced?

Interpretation Introduction

Interpretation:

The limiting reagent and the amount of SF6 produced in the given reaction have to be determined.

Concept introduction:

Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.

For chemical reaction balanced chemical reaction equation written in accordance with the

Law of conservation of mass.

Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.

### Explanation of Solution

Balanced chemical equation for the given reaction is,

S8(s)+24F2(g)8SF6(g)

The amount of SF6 produced can be determined by considering the amount of substance in both the reactant S8 and F2

Therefore the amount of SF6 produced is,

1.6molS8×8molSF61molS8=12

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