100.0 mL sample of natural water was titrated with NaOH. The titration required 10.25 mL of 0.1075 M NaOH solution to each a light pink phenolphthalein end point. Calculate the number of millimoles of NaOH required for the titration. Macr number of millimoles of NaOH = mm

100.0 mL sample of natural water was titrated with NaOH. The titration required 10.25 mL of 0.1075 M NaOH solution to each a light pink phenolphthalein end point. Calculate the number of millimoles of NaOH required for the titration. Macr number of millimoles of NaOH = mm

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter15: Complex Acid/base Systems

Section: Chapter Questions

Problem 15.29QAP

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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A multivitamin sample has a label claim of 500 mg ascorbic acid (176.12 g/mol). According to quality assurance guidelines for stability, it has an acceptable range of 90.0%-110.0% of the label claim. After production, the multivitamin was analyzed through acid-base titration, and the sample needed 25.40 mL of a 0.1101 M NaOH titrant to reach the end point. After 3 months, the same multivitamin was analyzed again, and this time 23.34 mL of the same 0.1101 M titrant was used. After 6 months, the same multivitamin was analyzed again, and this time, 22.48 mL of the same 0.1101 M NaOH titrant was needed to reach the end point.
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