100k 5.40 Referring to the circuit shown in Fig. 5.77, determine V. V₁ = = V0 = -4 V(= in terms of V₁ and V₂. V₁ (+ V₂ 100 ΚΩ + 100 ΚΩ W Va 200 k Va + 10 Ω ww Vo 15 + 40 Ω Σ V Vo √/₂=-=—= √₂ Se

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Q.40

V₁-va
LAK
V₁
√2-Va
Vs-Va
100k20
24 = 2Va+3Va
201= 5V/₂
V(= = -5V0-4
5.40 Referring to the circuit shown in Fig. 5.77, determine V.
in terms of V₁ and V₂.
+
V₂
Va-Vo
Sook
Figure 5.77
For Prob. 5.40.
100 ΚΩ
100 ΚΩ
-Vout
2 V₁-3√4 = -Vo
Va 200 k
ww
Va
=
+
-√₂-2-V0
Vo
10 Ω
www
(V₁ + V₂ + V3 + V4)
Problems
Vo
+
40 Ω Σ νο
5.41 An averaging amplifier is a summer that provides an
end output equal to the average of the inputs. By using
proper input and feedback resistor values, one can get
√₂=-=-= Vo
V₁ = - 21/0
-4
Using a feedback resistor of 10 k, design an averaging
amplifier with four inputs.
e
Se
L
Fig
For
Transcribed Image Text:V₁-va LAK V₁ √2-Va Vs-Va 100k20 24 = 2Va+3Va 201= 5V/₂ V(= = -5V0-4 5.40 Referring to the circuit shown in Fig. 5.77, determine V. in terms of V₁ and V₂. + V₂ Va-Vo Sook Figure 5.77 For Prob. 5.40. 100 ΚΩ 100 ΚΩ -Vout 2 V₁-3√4 = -Vo Va 200 k ww Va = + -√₂-2-V0 Vo 10 Ω www (V₁ + V₂ + V3 + V4) Problems Vo + 40 Ω Σ νο 5.41 An averaging amplifier is a summer that provides an end output equal to the average of the inputs. By using proper input and feedback resistor values, one can get √₂=-=-= Vo V₁ = - 21/0 -4 Using a feedback resistor of 10 k, design an averaging amplifier with four inputs. e Se L Fig For
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