The answer is already given. I just need the solution. Also, please make the solution neat and readable. Thank you.Answer: P= 281 lb 4'.4'B平6'2'W = 600 lbFigure P-11-4.10 11-4.10. The coefficient of friction under the sliding supports of thedoor in Fig. P-11-4.10 is 0.30 at A and 0.20 at B. What force P will givethe 600-lb door a leftward acceleration of 8.05 fps??P = 281 lbAns.

Answered: Image /qna-images/answer/56de9740-c233-4460-a5cc-dc2c66a7d996.jpg

11-4.10. The coefficient of friction under the sliding supports of the door in Fig. P-11-4.10 is 0.30 at A and 0.20 at B. What force P will give the 600-lb door a leftward acceleration of 8.05 fps2? P = 281 lb Ans.

11-4.10. The coefficient of friction under the sliding supports of the door in Fig. P-11-4.10 is 0.30 at A and 0.20 at B. What force P will give the 600-lb door a leftward acceleration of 8.05 fps2? P = 281 lb Ans.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

The answer is already given. I just need the solution. Also, please make the solution neat and readable. Thank you. Answer: P= 281 lb

4'.
4'
B
平
6'
2'
W = 600 lb
Figure P-11-4.10

11-4.10. The coefficient of friction under the sliding supports of the
door in Fig. P-11-4.10 is 0.30 at A and 0.20 at B. What force P will give
the 600-lb door a leftward acceleration of 8.05 fps??
P = 281 lb
Ans.

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