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A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees. The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kN My = 65kNm Mx = 40kNm The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0.  The Meyerhof bearing capacity factors are given below: What is the difference between the allowable bearing capacity and the maximum bearing pressure in kPa? 386.079 None of the choices 387.161 388.515 335.987 327.928 Please answer this asap. For upvote. Thank you very much

A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees. The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kN My = 65kNm Mx = 40kNm The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0.  The Meyerhof bearing capacity factors are given below: What is the difference between the allowable bearing capacity and the maximum bearing pressure in kPa? 386.079 None of the choices 387.161 388.515 335.987 327.928 Please answer this asap. For upvote. Thank you very much

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.

The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis

  • Vertical axial load = 256kN
  • My = 65kNm
  • Mx = 40kNm

The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. 

The Meyerhof bearing capacity factors are given below:

What is the difference between the allowable bearing capacity and the maximum bearing pressure in kPa?

386.079

None of the choices

387.161

388.515

335.987

327.928

Please answer this asap. For upvote. Thank you very much

$ (deg) N. N O (deg) N. N, 5-14 1.00 0.000 26 22.25 11.85 8.002 5-38 1.09 0.002 27 23.94 13.20 9-463 5.63 28 25.80 1.20 0.010 14.72 11.190 3. 5-90 131 0.023 29 27.86 16.44 13.236 4. 6.19 1.43 0.042 30 30.14 18.40 15.668 6.49 1.57 0.070 31 32.67 20.63 18.668 6. 6.81 1.72 0.106 35-49 23.18 32 22.022 7.16 1.88 0.152 33 38.64 26.09 26.166 8. 7-53 2.06 0.209 34 42.16 29.44 31.145 6. 7-92 2.25 0.280 35 46.12 33-30 37-152 10 8.35 2.47 0.367 36 50.59 37-75 44426 11 8.80 2.71 0.471 37 55,63 42.92 53-270 12 9-28 2.97 0.596 38 61.35 48.93 64.073 13 9.81 3-26 0.744 39 67.87 55-96 7-332 14 10.37 3-59 0.921 40 75-31 64.20 93-690 15 10.98 3-94 1.129 41 83.86 73-90 113.985 16 11.63 434 1.375 42 93-71 85-38 139-985 17 12.34 477 1.664 43 105.11 99.02 171.141 18 13.10 5-26 2.003 44 118.37 115.31 211.406 19 13-93 5.80 2.403 45 133.88 134.88 262.739 14.83 6.40 2.871 46 158.51 328.728 20 152.10 21 15.82 7.07 3-421 47 173.64 187.21 414-322 22 16.88 7.82 4,066 48 199.26 222.31 526.444 23 18.05 8.66 4,824 49 229-93 265-51 674-908 24 19-32 9.60 5-716 50 266.89 319.07 873.843 25 20.72 10.66 6.765
Transcribed Image Text:$ (deg) N. N O (deg) N. N, 5-14 1.00 0.000 26 22.25 11.85 8.002 5-38 1.09 0.002 27 23.94 13.20 9-463 5.63 28 25.80 1.20 0.010 14.72 11.190 3. 5-90 131 0.023 29 27.86 16.44 13.236 4. 6.19 1.43 0.042 30 30.14 18.40 15.668 6.49 1.57 0.070 31 32.67 20.63 18.668 6. 6.81 1.72 0.106 35-49 23.18 32 22.022 7.16 1.88 0.152 33 38.64 26.09 26.166 8. 7-53 2.06 0.209 34 42.16 29.44 31.145 6. 7-92 2.25 0.280 35 46.12 33-30 37-152 10 8.35 2.47 0.367 36 50.59 37-75 44426 11 8.80 2.71 0.471 37 55,63 42.92 53-270 12 9-28 2.97 0.596 38 61.35 48.93 64.073 13 9.81 3-26 0.744 39 67.87 55-96 7-332 14 10.37 3-59 0.921 40 75-31 64.20 93-690 15 10.98 3-94 1.129 41 83.86 73-90 113.985 16 11.63 434 1.375 42 93-71 85-38 139-985 17 12.34 477 1.664 43 105.11 99.02 171.141 18 13.10 5-26 2.003 44 118.37 115.31 211.406 19 13-93 5.80 2.403 45 133.88 134.88 262.739 14.83 6.40 2.871 46 158.51 328.728 20 152.10 21 15.82 7.07 3-421 47 173.64 187.21 414-322 22 16.88 7.82 4,066 48 199.26 222.31 526.444 23 18.05 8.66 4,824 49 229-93 265-51 674-908 24 19-32 9.60 5-716 50 266.89 319.07 873.843 25 20.72 10.66 6.765
Shape Factors Component For o = 0 For o > 10 Cohesion Aa =1+0.2 d =1+0.2 tan 45 + Surcharge dg = 1 =1+0.1 tan 45 + Unit Weight Ayn = 1 Ay = Ag Depth Factors Component For = 0° For o > 10° Cohesion Aed =1+0.2 Aed =1+0.2 tan 45+ Surcharge Agd = 1 Agr = 1+0.1 tan 45 + B Unit Weight Ayd = 1 Ayd = Agd Inclination Factors Component Formula Cohesion di = 90° Surcharge 90 B- width of the footing D, = depth of footing L- length of the footing Unit Weight
Transcribed Image Text:Shape Factors Component For o = 0 For o > 10 Cohesion Aa =1+0.2 d =1+0.2 tan 45 + Surcharge dg = 1 =1+0.1 tan 45 + Unit Weight Ayn = 1 Ay = Ag Depth Factors Component For = 0° For o > 10° Cohesion Aed =1+0.2 Aed =1+0.2 tan 45+ Surcharge Agd = 1 Agr = 1+0.1 tan 45 + B Unit Weight Ayd = 1 Ayd = Agd Inclination Factors Component Formula Cohesion di = 90° Surcharge 90 B- width of the footing D, = depth of footing L- length of the footing Unit Weight
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