(11) When the conditional density of X given Y = y E (0, 1) is 2x fxjY=y(x) = y < x < 1. 1 – y2 ' Compute E(X|Y = 0.25). 0.7 0.25 0.75 2 None of the above N/A (Select One)

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.3: Least Squares Approximation
Problem 32EQ
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Please just answer problem 14. Problem 11 & 13 is attached to help you. 

(13) For the conditional density given in problem (11) above obtain Var(X|Y = y) for y E (0, 1).
The following expressions are proposed.
1+y?
2
2(1+y+y?)
(a) Var(X|Y = y) =
2
3(1+y)
2
1+y?
(b) Var(X|Y = y) =
2y²
{
- {
2(1+y+y*) \°
2
3(1+y)
1+y?
(c) Var(X|Y = y) =
2
2
3(1+y)
1-y?
(d) Var(X|Y = y) =
2
3(1+y)
(e) None of the above
(a)
(b)
(c)
(d)
(e)
N/A
(Select One)
(14) For the last problem, what is Var(X|Y):
The following expressions are proposed.
2(1+Y+Y?)
2
1+Y2
(a) Var(X|Y) =
-
2
3(1+Y)
1+y2
2Y2
(b) Var(X|Y) =
-
3(1+Y)
1+y2
(c) Var(X|Y) =
3(1+Y)
1-y2
2(1+Y+Y²)
(d) Var(X|Y) =
2
3(1+Y)
(e) None of the above
(a)
(b)
(c)
(d)
(e)
N/A
(Select One)
Transcribed Image Text:(13) For the conditional density given in problem (11) above obtain Var(X|Y = y) for y E (0, 1). The following expressions are proposed. 1+y? 2 2(1+y+y?) (a) Var(X|Y = y) = 2 3(1+y) 2 1+y? (b) Var(X|Y = y) = 2y² { - { 2(1+y+y*) \° 2 3(1+y) 1+y? (c) Var(X|Y = y) = 2 2 3(1+y) 1-y? (d) Var(X|Y = y) = 2 3(1+y) (e) None of the above (a) (b) (c) (d) (e) N/A (Select One) (14) For the last problem, what is Var(X|Y): The following expressions are proposed. 2(1+Y+Y?) 2 1+Y2 (a) Var(X|Y) = - 2 3(1+Y) 1+y2 2Y2 (b) Var(X|Y) = - 3(1+Y) 1+y2 (c) Var(X|Y) = 3(1+Y) 1-y2 2(1+Y+Y²) (d) Var(X|Y) = 2 3(1+Y) (e) None of the above (a) (b) (c) (d) (e) N/A (Select One)
(11) When the conditional density of X given Y = y E (0, 1) is
2x
fx\Y=y (x) =
y < x < 1.
1 – y² ’
Compute E(X|Y = 0.25).
0.7
0.25
0.75
None of the above
N/A
(Select One)
Transcribed Image Text:(11) When the conditional density of X given Y = y E (0, 1) is 2x fx\Y=y (x) = y < x < 1. 1 – y² ’ Compute E(X|Y = 0.25). 0.7 0.25 0.75 None of the above N/A (Select One)
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