11. L= {w|w € (0,1)* and |w| is even} 12. L= {w|w E (0,1)* and |w| is odd} 13.{ ab"c"d" | n odd, m even }
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- int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p1 int[] a = new int[n]; 2 a[0] = 0; a[1] = 1; 3 int x = 0; 4 for (int i = 2; i < n; i++) { 5 x = 3 * (i-1) * (i-1); 6 x += 3 * i - 2; 7 a[i] = a[i-1] + x; 8 } The code can be simplified by replacing lines 5, 6, 7 with a single line of code. Write the single line of code below:Q1.com Code. Given a 2d grid map of '1's (land) and '0's (water),count the number of islands.An island is surrounded by water and is formed byconnecting adjacent lands horizontally or vertically.You may assume all four edges of the grid are all surrounded by water. Example 1: 11110110101100000000Answer: 1 Example 2: 11000110000010000011Answer: 3""" def num_islands(grid): count = 0 for i in range(len(grid)): for j, col in enumerate(grid[i]): if col == 1: dfs(grid, i, j) count += 1 Please code it. .
- 6.Code for an array of meeting time intervals consisting ofstart and end times [[s1,e1],[s2,e2],...] (si < ei),determine if a person could attend all meetings. For example,Given [[0, 30],[5, 10],[15, 20]],return false.""".in python “c” represents a crop and “w” represents a water source. Each water source hydrates the eight tiles around it (including itself) Input the number of rows and columns in the crop field:ROWS> 4COLUMNS> 4Input each row of the crop field.ROW0> c c c wROW1> w c c cROW2> c c c cROW3> c w c cNot all crops are watered!OUTPUT FalseThe following crops are not watered:OUTPUT [(2, 3), (3, 3)] Input the number of rows and columns in the crop field:ROWS> 7COLUMNS> 1Input each row of the crop field.ROW0> cROW1> wROW2> cROW3> cROW4> wROW5> cROW6> wAll crops are watered!OUTPUT Trueint c[2][3]; int a[2][3] ={ {5}, {1,2} }; int b[2][3] = { 2,4,6,8} for( int i=0; i<2 ;i++)5. for( int j=0; j<3 ; j++) c[i] [j] = 3 * ( a[i] [j] + b[i] [j] ); program with c++
- python In order to beat AlphaZero, Grandmaster Hikaru is improving her chess calculation skills.Today, Hikaru took a big chessboard with N rows (numbered 1 through N) and N columns (numbered 1 through N). Let's denote the square in row r and column c of the chessboard by (r,c). Hikaru wants to place some rooks on the chessboard in such a way that the following conditions are satisfied:• Each square of the board contains at most one rook.• There are no four rooks forming a rectangle. Formally, there should not be any four valid integers r1, c1, r2, c2 (≠r2,c1≠c2) such that there are rooks on squares (r1,c1), (r1,c2 (r2,c1)and (r2,c2).• The number of rooks is at least 8N.Help Hikaru find a possible distribution of rooks. If there are multiple solutions, you may find any one. It is guaranteed that under the given constraints, a solution always exists.InputThe first line of the input contains a single integer T denoting the number of test cases. The first and only line of each test case…1. A set of integers are relatively prime to each other if there is no integer greater than 1 that divides all the elements. Furthermore, in Number Theory, it is known that the Euler function,ϕ (n), expresses the number of positive integers less than n that are relatively prime with n. Choose the alternative that has the correct value of ϕ(n) for every n below. A) ϕ(5) = 4 B) ϕ(6) = 2 C) ϕ(10) = 3 D) ϕ(14) = 6 E) ϕ(17) = 163. Write a program in C++ to store all the numbers between n and m into an array using a loop. (Note: n <= m). 4. Write a program in C++ to store all odd numbers between n and m into an array using a loop. (Note: n can be greater, equal or less than m and |n-m|<=100). 5. Write a program that accepts two arrays of integers and print true if the first array is equal to the second array, otherwise print false. 6. Write a program in C++ that constructs a two-dimensional array of integers with 6 rows and 8 columns. Fill the array with a multiplication table, so that array element [i][j] contains the value i * j. Then print the array as a table.
- 2. JAVA Programming Arrays a1, a2… are populated as shown; display a[i] for each calls to arr; if a[i] less than or equal to 0 display a message indicating those conditions public static void arr(int[] a) { //Add the missing loop a[i] = a[i + 1] + a[i - 1]; // display a[i] } } a1 = 3, 7 a2 = 4, 7, 4, 2, 10, 9 a3 = 1, 5, 0, 0, 5, 0 a4 = 13, 0, -4, -2, 0, -1 a5 = 2, 4, 6, 8, 16Java: Arrays a1, a2… are populated as shown; display a[i] for each calls to arr; if a[i] less than or equal to 0 display a message indicating those conditions public static void arr(int[] a) { //Add the missing loop a[i] = a[i + 1] + a[i - 1]; // display a[i] } } a1 = 3, 7 a2 = 4, 7, 4, 2, 10, 9 a3 = 1, 5, 0, 0, 5, 0 a4 = 13, 0, -4, -2, 0, -1 a5 = 2, 4, 6, 8, 16Write a program named as reverse.c that reads a message, then prints the reversal of the message. The output of the program should look like this: Enter a message: Don ’t get mad, get even. Reversal is : .neve teg ,dam teg t ’noD Hint: Read the message one character at a time (using getchar) and store the characters in an array. Stop Reading when the array is full or the character read is ‘\n’. The framework of reverse.c is as below: /* reverse.c */ #include #define N 50 int main(){ int arr[N],i=0; char ch; printf("Enter a message: "); /* Put code here to get input from user by using getchar() */ printf("Reversal is: "); /* Put code here to print out the reversal by using putchar()*/ printf("\n"); return 0; }