11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon. CH₂OH H O OH H H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H OH H O 0 H OH H OH H O CH₂OH c) H, HO CH₂OH H OH H O H ОН H HO H H O Hemiacetal carbon. CH UM H OH H H D-glucose (cyclic form) OH CH₂OH R 0. H 0 OH H ОН OH H OH H H OH

Organic Chemistry: A Guided Inquiry
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ISBN:9780618974122
Author:Andrei Straumanis
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Chapter17: Conjugation And Molecular Orbital (mo) Theory
Section: Chapter Questions
Problem 12E
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I need help with number 24 because I struggle with my homework. I don't understand. Can you explain to me, please?

11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal
is a molecule that contains both an OR group and an OH group that are bonded to the same
carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal
carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that
is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you.
However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated
by the red arrow in the structures shown on the right, the OR bonding pattern is seen.
QUESTION: Which of the molecules shown below contain a hemiacetal carbon?
a)
Hemiacetal
Carbon-
CH₂OH
H
O
OH H
L
H
OH
OH
CH₂OH
b)
H
HO
CH₂OH
H
CH₂OH
H
OH
H
0.
H
H
OH
OH H
OH
H
O
CH₂OH
c)
H
HO
CH₂OH
H
OH
H
O
H
OH
H
HO
O
H H
CH UM
Hemiacetal carbon-
H
OH
H
D-glucose
(cyclic form)
R
H
CH₂OH
+
H
OH
H
O
-0.
OH H
OH
OH
H
OH
H
H
OH
Transcribed Image Text:11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon- CH₂OH H O OH H L H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H 0. H H OH OH H OH H O CH₂OH c) H HO CH₂OH H OH H O H OH H HO O H H CH UM Hemiacetal carbon- H OH H D-glucose (cyclic form) R H CH₂OH + H OH H O -0. OH H OH OH H OH H H OH
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