11.95To approximate an actual spark-ignition engine consider an air-standard Ottocycle that has a heat addition of 1800 kJ/kg of air, a compression ratio of 7, and apressure and temperature at the beginning of the compression process of 90 kPa,10°C. Assuming constant specific heat, with the value from Table A.5, determinethe maximum pressure and temperature of the cycle, the thermal efficiency of thecycle and the mean effective pressure.Solution:IAPNCompression: Reversible and adiabatic so constants from Eq.8.33-34P₂ P₁(v₁/v₂) 90(7)¹.4-1372 kPaT₂=T₁(v₁/v₂)k-1=283.2 × (7)0.4 = 616.6KTCombustion: constant volumeT3 T₂+9H/Cv0 = 616.6+1800/0.717=3127 KP3 P₂T3/T2= 1372 x 3127/616.6=6958 kPaEfficiency and net workTH 1-T₁/T₂ 1-283.2/616.5=0.541Wnet-THX9H=0.541 x 1800-973.8 kJ/kgDisplacement and PmeffV₁-RT₁/P₁-(0.287 x 283.2)/90-0.9029 m³/kgV₂=(1/7) v₁ = 0.1290 m³/kgPmeff973.8WNETV₁-V₂ 0.9029-0.1291258 kPa

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11.95 To approximate an actual spark-ignition engine consider an air-standard Otto cycle that has a heat addition of 1800 kJ/kg of air, a compression ratio of 7, and a pressure and temperature at the beginning of the compression process of 90 kPa, 10°C. Assuming constant specific heat, with the value from Table A.5, determine the maximum pressure and temperature of the cycle, the thermal efficiency of the cycle and the mean effective pressure. Solution: IAP 2 Compression: Reversible and adiabatic so constants from Eq.8.33-34 P2-P₁(v₁/v₂)-90(7)¹.4-1372 kPa T₂-T₁(v₁/v₂)-1 283.2 x (7)0.4-616.6 K Combustion: constant volume T T3 T₂+qu/Cvo=616.6+1800/0.717-3127 K P3 P₂T/T2 1372 x 3127/616.6-6958 kPa Efficiency and net work TH 1-T₁/T₂ 1-283.2/616.5=0.541 Wnet NTH XH-0.541 x 1800-973.8 kJ/kg Displacement and Pmeff V₁-RT₁/P₁-(0.287 x 283.2)/90-0.9029 m³/kg V₂ (1/7) v₁0.1290 m³/kg WNET 973.8 Pmeff V₁-V₂ 0.9029-0.129 1258 kPa

11.95 To approximate an actual spark-ignition engine consider an air-standard Otto cycle that has a heat addition of 1800 kJ/kg of air, a compression ratio of 7, and a pressure and temperature at the beginning of the compression process of 90 kPa, 10°C. Assuming constant specific heat, with the value from Table A.5, determine the maximum pressure and temperature of the cycle, the thermal efficiency of the cycle and the mean effective pressure. Solution: IAP 2 Compression: Reversible and adiabatic so constants from Eq.8.33-34 P2-P₁(v₁/v₂)-90(7)¹.4-1372 kPa T₂-T₁(v₁/v₂)-1 283.2 x (7)0.4-616.6 K Combustion: constant volume T T3 T₂+qu/Cvo=616.6+1800/0.717-3127 K P3 P₂T/T2 1372 x 3127/616.6-6958 kPa Efficiency and net work TH 1-T₁/T₂ 1-283.2/616.5=0.541 Wnet NTH XH-0.541 x 1800-973.8 kJ/kg Displacement and Pmeff V₁-RT₁/P₁-(0.287 x 283.2)/90-0.9029 m³/kg V₂ (1/7) v₁0.1290 m³/kg WNET 973.8 Pmeff V₁-V₂ 0.9029-0.129 1258 kPa

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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