11047Ag → 0.je + 110 48Cd For the nuclear reaction Starting with 200. g of Ag-110 in a container, how long will it take to decay to only 6.25 g ? The half-life of Ag-110 is 252 days. times. For each half-life we divide by 2. So, in order to reach 6.25 g we have to divide 200. g by 2 The number of half-lives is

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For the nuclear reaction
11047Ag → 0-1e +
110 48Cd
Starting with 200. g of Ag-110 in a container, how long will it take to decay to only 6.25 g? The half-life of Ag-110 is 252 days.
For each half-life we divide by 2. So, in order to reach 6.25 g we have to divide 200. g by 2
times.
The number of half-lives is
Each half-life is 252 days so we multiply this by the number of half-lives. The time required is thus
days.
The total mass in the container is still about
g. Most of the mass is now
а. 200.
b. 110
С. 100.
d. 50.0
е. 25.0
f. 12.5
g. 6.25
h. Ag-110
i. Cd-110
j. electron
k. 756
I. 1
m. 2
n. 3
О. 4
р. 5
q. 6
r. 7
S. 1512
t. 1260
u. 1008
V. 756
w. 504
Transcribed Image Text:For the nuclear reaction 11047Ag → 0-1e + 110 48Cd Starting with 200. g of Ag-110 in a container, how long will it take to decay to only 6.25 g? The half-life of Ag-110 is 252 days. For each half-life we divide by 2. So, in order to reach 6.25 g we have to divide 200. g by 2 times. The number of half-lives is Each half-life is 252 days so we multiply this by the number of half-lives. The time required is thus days. The total mass in the container is still about g. Most of the mass is now а. 200. b. 110 С. 100. d. 50.0 е. 25.0 f. 12.5 g. 6.25 h. Ag-110 i. Cd-110 j. electron k. 756 I. 1 m. 2 n. 3 О. 4 р. 5 q. 6 r. 7 S. 1512 t. 1260 u. 1008 V. 756 w. 504
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