1136.) Tho sido rod of the onginc in Fig. P-1136 is sfl long woighs 100 lb. The cranks AD BC aro of longhtr• 18 in. rotate al 300 rpm. Delorminc the maximum bonding momont M in the rod if M • WL/8, whero W ic tho total dictributod load kL is the longht of the nod. NSWERS: M=100 lb-ft
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- Determine the vatatron at of the frame shown in higuve. E: 2001o mpa I- 3. *1o mm 4 point Take 1ompa I- 3. * lo mmy SEN く。 Liseda) The components of the apparatus were assembled by the technician. b) Firstly, weigh the aluminium beam given on the measuring scale, with a span of 1000mm. c) Place both spring balances with Newton readings on the left and right end of the frame. 2 d) Zero the two spring balances. e) Load the beam on both spring balances, at Omm from the left end of the beam and at 1000mm on the right end of the beam ) With the use of two metal hangers, place the one metal hanger was at 200mm from the left-hand side of the beam and at 100mm from the right-hand side of the beam, thereafter both hangers will be loaded with loads/weights g) Load left hanger with 400g and right hanger with 500g h) Read and record the readings from both the spring balances as left and right reactions in newtons (N). RESULTS 400g 603.7g 500g 200mm 100mm 500mm 1000mm RL RR Figure 3. Experimental Force diagram of a simply supported beam.The uniferm arcer ectangular thin plate has dimensicrs indicated and mass M- 52 kg. 2.3 T 4.5 n Decermine the mass moment of inertia in kgm- and the rsdius of gyration in meters of the thin pate about an axis through point O cirected perpendicular to the p are of the page. Peint 3 is ccsted at the upper left corner ef the pate. 'o =
- @determine the magnitudo the magnitude of the vesulHant force of fhe coplarer force Syste shoun in the figure below uhere the horizental force p=123N ard the couple M= 503NM N.m 1SON 300mm 400 mm €) determine the distance Fror Orinm) at which this should be placed so that res Hant the syster is replaced entirely by a single force.600 N 600 N 200 N [02 m 200 N - 3m - 300 N 300 N Determine the resultant couple moment acting on the beam. O 340 Nm CW O 120 Nm CCW O 340 Nm CCW O 280 Nm CWLTE Asiacell li. A docs.google.com AA Determine the resultant of moment about point O and magnitude of F1 and F2 acting on the rod shown in fig. below. if known the value of a =20 and the magnitude of weight 30 N. the resultant acted on Y- positive equal 100 N. 1-5m FI F2 B wieght 1 Add File Вack Next >
- The two forces acting on the handles of the pipe wrenches constitute a couple 'M'. Express the couple as a vector Z 150 N 250 mm B 150 N OM -75i+22.5j N.m OM -75i+2.5j N.m OM -85i+22.5j N.m 150 mm 250 mmQuestions kasainta05h_chp16.17m What is the fixed end moment FEMAB for the beam with a settlement of 25 mm at support C? 20 kN/m 60 kN 5. E D -8 m+am+4m 7. -8 m El - constant E= 70 GPa /= 800 (10) mm 10. O 713 kN-m O0.1913 N-m O 230.0 N-m O a 106 7AN-m. A Simply Supported Concete beam havig a width of so rn and an effectire hepth g s2oma carries a load includmg its Wergth Wq= 7 kNm and a loncortated loád Pa: 370KN unforaly distributed fectret acting 2m from Peft Support. fi = 207 Apa, fo: 415 Mpa I det the Max factored Shear force. at the Cntical Seetion. 2 det the Spaang of the lo'mm o belween. A to B s det. the Spacing the lommd of Sstrirups between B-C. R370KN A B
- This force-couple system is to be replaced by an equivalent system consisting of the following: a couple moment Mx, and a single force, Rc acting at C. Draw the diagram for the equivalent system and determine Mx and Rc. A 100N 80N 110N-m Thislis not your 50N 150N own propenty so do nbt use it in 50N any way asliffit were your dwn. 130 N D C 180N-m 12° 3ON fhis is hot your own propery so đo not use t n any way as f it were your own. 1m B EHwiDetermine the internal forces acting on the cross-Section of Bints H and E of the frame shown ? NH= 527N , VH=37BN, MH= 373 Nim NE 75N Ansi VE 355N, ME= 727 Nim 4m 75N/m 3m 3 mA 540-N weight 8tarts down a 30' inch'ne with an initial velscity y 3m/s. Fird the velscity the weight & s if after the inchine. fe 0.a5 for