#12 A 95 kg student is standing on rollerblades at rest. The student then catches a 5 kg bowling ball that has a velocity of +5 m/s. a. What is the momentum of the student before the collision? P2= 5kg m=5m/s m= V= v= Your answer here total b. What is the momentum of the bowling ball before the collision? P,= P2= m= m=

Physics for Scientists and Engineers: Foundations and Connections
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Chapter11: Collisions
Section: Chapter Questions
Problem 7PQ: Sven hits a baseball (m = 0.15 kg). He applies an average force of 50.0 N. The ball had an initial...
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A 95 kg student is standing on rollerblades at rest. The student then catches a 5 kg
bowling ball that has a velocity of +5 m/s.
#12
c. What is the total momentum of the system?
P2=
Your answer here
m=
m=
V=
v=
total
d. What is the final velocity of the student and bowling ball together
after the collision?
P3=
Your answer here
m=
v=
total
Transcribed Image Text:A 95 kg student is standing on rollerblades at rest. The student then catches a 5 kg bowling ball that has a velocity of +5 m/s. #12 c. What is the total momentum of the system? P2= Your answer here m= m= V= v= total d. What is the final velocity of the student and bowling ball together after the collision? P3= Your answer here m= v= total
A 95 kg student is standing on rollerblades at rest. The student then catches a 5 kg
bowling ball that has a velocity of +5 m/s.
#12
a. What is the momentum of the student before the
P2= 5kg
m=5m/s
collision?
m=
v=
V=
Your answer here
total
b. What is the momentum of the bowling
ball before the collision?
P,=
P2=
m=
m=
Your answer here
V=
v=
P..=
total
Transcribed Image Text:A 95 kg student is standing on rollerblades at rest. The student then catches a 5 kg bowling ball that has a velocity of +5 m/s. #12 a. What is the momentum of the student before the P2= 5kg m=5m/s collision? m= v= V= Your answer here total b. What is the momentum of the bowling ball before the collision? P,= P2= m= m= Your answer here V= v= P..= total
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