12-phase ∆-connected 3200 V (line-to-line), 12,000 kW, 50 Hz, twelve-pole squirrel-cage induction drive is designed for electric vehicle use. The drive has the following equivalent parameter values in Ω/phase referred to the stator: R1= 0.697 Ω R2= 0.328 Ω Rm1 = 226 Ω X1 = 0.549 Ω X2 = 0.456 Ω Xm1 = 31.573 Ω The total friction, windage, and core losses are assumed to be constant at Plosses= 1156 W, independent of load. a)Draw the equivalent circuit for this drive and show the relevant parameters on the circuit. For a slip value of s = 0.032 and using the above equivalent circuit parameters, determine: b) The stator current and the power factor c) The synchronous speed and the rotor speed for this drive

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A 12-phase ∆-connected 3200 V (line-to-line), 12,000 kW, 50 Hz, twelve-pole
squirrel-cage induction drive is designed for electric vehicle use. The drive has the
following equivalent parameter values in Ω/phase referred to the stator:
R1= 0.697 Ω R2= 0.328 Ω Rm1 = 226 Ω
X1 = 0.549 Ω X2 = 0.456 Ω Xm1 = 31.573 Ω
The total friction, windage, and core losses are assumed to be constant at Plosses=
1156 W, independent of load.
a)Draw the equivalent circuit for this drive and show the relevant parameters on
the circuit.
For a slip value of s = 0.032 and using the above equivalent circuit parameters,
determine:

b) The stator current and the power factor

c) The synchronous speed and the rotor speed for this drive

d) The torque generated
e) The input power for this operating condition
f) The efficiency when operated at rated voltage and frequency
g) Considering the design of this motor, state if it is possible to start this drive with
a slip ring starter. Give reasons to justify your answer. just need answer from d to f

2 (b) Î1=295.430 - j113.970 A = 316.650 Z-21.095 °
(c) ns = 5000 r.min-1, nr=484 r.min-1
(d) Tshaft 1.919×105 N·m
(e) Pin=1.134×107 W
(f) n =85.737 %.
Transcribed Image Text:2 (b) Î1=295.430 - j113.970 A = 316.650 Z-21.095 ° (c) ns = 5000 r.min-1, nr=484 r.min-1 (d) Tshaft 1.919×105 N·m (e) Pin=1.134×107 W (f) n =85.737 %.
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