**12. A 1200-kg car is being driven up a 5.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force Fy directed perpendicular to the road surface. The length of the road up the hill is 290 m. What should be the magnitude of F, so that the net work done by all the forces acting on the car is +150 kJ?

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
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Chapter8: Conservation Of Energy
Section: Chapter Questions
Problem 8.78AP
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**12. A 1200-kg car is being driven up a 5.0° hill. The frictional force
is directed opposite to the motion of the car and has a magnitude of
f = 524 N. A force F is applied to the car by the road and propels the car
forward. In addition to these two forces, two other forces act on the car: its
weight W and the normal force Fy directed perpendicular to the road
surface. The length of the road up the hill is 290 m. What should be
the magnitude of F, so that the net work done by all the forces acting
on the car is +150 kJ?
Transcribed Image Text:**12. A 1200-kg car is being driven up a 5.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force Fy directed perpendicular to the road surface. The length of the road up the hill is 290 m. What should be the magnitude of F, so that the net work done by all the forces acting on the car is +150 kJ?
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