120t, howe looge toot friend (-) 700ft 500ft store CODT dinates of (+120 Cos45 i+120 sinys) coordinatel of I, point (6052 - 100 CosI0 (-13-63 Here point I (50.5, 60E) Now (6052 +r00 Si1o) 102:21) of friend's -13-63- 700 Cos30 (-619 -04 %3D Coo rdinates location 102:21-00Sin (30°)) 247.79) N° of East tane 247-79 619-84 21.9° N of_Eal t Magnitude 667.5

University Physics Volume 1
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Chapter2: Vectors
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Problem 21CQ: What is wrong with the following expressions? How can you correct them? (a) C=AB , (b) C=AB , (c)...
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Hi, I would just like to ask why is it necessary to use the acquired coordinates from point 1 in order to acquire the coordinates of point 2, the same way that the acquired coordinates from point 2 were used to acquire the coordinates of the friends locatio?. Thank you.

t20ft op)
howe
100
toot
friend
700ft
sto re
point I
+120 Cos45+ (20 siny5)
coordinatel of point I,
(6o52- 100 Cos10°
(-13:63 , 102:21).
Coo rdinate of friend's
-13-63- 400 cos30
(-619 .04
Here
COordinatesof
- (8052, 60.52)
Now
(6052 +100 Sinio)
Sinio").
%3D
location
102.21-00sin (30°))
247.79)
N° of East
tane
247-79
619.84
21.9°
N° of Galt
Magnitude
664:5ft
Transcribed Image Text:t20ft op) howe 100 toot friend 700ft sto re point I +120 Cos45+ (20 siny5) coordinatel of point I, (6o52- 100 Cos10° (-13:63 , 102:21). Coo rdinate of friend's -13-63- 400 cos30 (-619 .04 Here COordinatesof - (8052, 60.52) Now (6052 +100 Sinio) Sinio"). %3D location 102.21-00sin (30°)) 247.79) N° of East tane 247-79 619.84 21.9° N° of Galt Magnitude 664:5ft
(- 619 - 84
location
location= (500 Cos4o°, 500 8inyo)
(303.02
need
Jc002:86)2 + (569. 18)*
(B)
priend's
-247-79
Store
321. 39)
distance
to
wallk
1133-08ft
Distance
1183 08 ft
tane
569 18
0.0099
%3D
1002-86
56.17°
90
N° of W
561年。
338 3°
s° of w
Transcribed Image Text:(- 619 - 84 location location= (500 Cos4o°, 500 8inyo) (303.02 need Jc002:86)2 + (569. 18)* (B) priend's -247-79 Store 321. 39) distance to wallk 1133-08ft Distance 1183 08 ft tane 569 18 0.0099 %3D 1002-86 56.17° 90 N° of W 561年。 338 3° s° of w
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