123 E(8 – 6k + 2k? k=1 3k) =

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 38WE
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123
E (8 – 6k + 2k² – 3k³) =
k=1
Transcribed Image Text:123 E (8 – 6k + 2k² – 3k³) = k=1
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