12% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 334 people from the inner city surveyed, 37 of them suffered from sleep apnea. What can be concluded at the level of significance of a = 0.10? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? ? v (please enter a decimal) Hj: ? ▼ (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 12%. The data suggest the populaton proportion is significantly different from 12% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 12% The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 12%. h. Interpret the p-value in the context of the study. O There is a 60.4% chance that the percent of all inner city residents have sleep apnea differs from 12%. There is a 60.4% chance of a Type I error. O If the sample proportion of inner city residents who have sleep apnea is 11% and if another 334 inner city residents are surveyed then there would be a 60.4% chance that we would conclude either fewer than 12% of all inner city residents have sleep apnea or more than 12% of all inner city residents have sleep apnea. O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner city residents are surveyed then there would be a 60.4% chance that either fewer than 11% of the 334 inner city residents surveyed have sleep apnea or more than 13% of the 334 inner city residents have sleep apnea. i. Interpret the level of significance in the context of the study. O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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12% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the
inner city have sleep apnea. Of the 334 people from the inner city surveyed, 37 of them suffered from sleep apnea. What
can be concluded at the level of significance of a = 0.10?
a. For this study, we should use Select an answer
b. The null and alternative hypotheses would be:
Но: ?
? v
(please enter a decimal)
Hj: ? ▼
(Please enter a decimal)
c. The test statistic ? v
(please show your answer to 3 decimal places.)
d. The p-value =
(Please show your answer to 4 decimal places.)
e. The p-value is ? v
f. Based on this, we should Select an answer v the null hypothesis.
g. Thus, the final conclusion is that
The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is
not sufficient evidence to conclude that the population proportion of inner city residents who have sleep
apnea is different from 12%.
The data suggest the populaton proportion is significantly different from 12% at a = 0.10, so there is
sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea
is different from 12%
The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is
sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea
is equal to 12%.
h. Interpret the p-value in the context of the study.
O There is a 60.4% chance that the percent of all inner city residents have sleep apnea differs from 12%.
There is a 60.4% chance of a Type I error.
O If the sample proportion of inner city residents who have sleep apnea is 11% and if another 334 inner city
residents are surveyed then there would be a 60.4% chance that we would conclude either fewer than 12%
of all inner city residents have sleep apnea or more than 12% of all inner city residents have sleep apnea.
O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner
city residents are surveyed then there would be a 60.4% chance that either fewer than 11% of the 334 inner
city residents surveyed have sleep apnea or more than 13% of the 334 inner city residents have sleep apnea.
i. Interpret the level of significance in the context of the study.
O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner
city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that
Transcribed Image Text:12% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 334 people from the inner city surveyed, 37 of them suffered from sleep apnea. What can be concluded at the level of significance of a = 0.10? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? ? v (please enter a decimal) Hj: ? ▼ (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 12%. The data suggest the populaton proportion is significantly different from 12% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 12% The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 12%. h. Interpret the p-value in the context of the study. O There is a 60.4% chance that the percent of all inner city residents have sleep apnea differs from 12%. There is a 60.4% chance of a Type I error. O If the sample proportion of inner city residents who have sleep apnea is 11% and if another 334 inner city residents are surveyed then there would be a 60.4% chance that we would conclude either fewer than 12% of all inner city residents have sleep apnea or more than 12% of all inner city residents have sleep apnea. O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner city residents are surveyed then there would be a 60.4% chance that either fewer than 11% of the 334 inner city residents surveyed have sleep apnea or more than 13% of the 334 inner city residents have sleep apnea. i. Interpret the level of significance in the context of the study. O If the population proportion of inner city residents who have sleep apnea is 12% and if another 334 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that
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