Hello, I need help with 13. Please and thank you. In the depths of space, asteroid miners attach a cable between their 3,694.-kg spaceship and a relatively small 1476-kgasteroid. The ship and asteroid are initially at rest 751 m apart. They begin to “reel in" the asteroid under a constant tensionof 512.0 N. We are going to calculate how long it takes take for them to meet. This is a somewhat complicated questioninvolving several different concepts, so let's just take it step by step.11.Draw free-body diagrams for the asteroid, and for the spaceship.Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively. i(a) aa = 0.3469 m/s²; a, = 0.1386 m/s²(b) aa = 0.1386 m/s²; a, = 0.3469 m/s²(c) a, = 0.1388 m/s²; a̟ = 0.2775 m/s²(d) aa = 0.2775 m/s²; a̟ = 0.1388 m/s²12.13.Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship.(a) 0.2083 m/s²(b) 0.4163 m/s²(c) 0.1387 m/s²(d) 0.4855 m/s²14.Calculate the time it takes for the asteroid and the spaceship to arrive at the same location. G(a) 104 s(b) 84.9 s(с) 60.1 s(d) 55.6 s

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Answered: 13. Calculate the magnitude of the…

13. Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. (a) 0.2083 m/s² (b) 0.4163 m/s² (c) 0.1387 m/s² (d) 0.4855 m/s²

Physics for Scientists and Engineers, Technology Update (No access codes included)

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Chapter14: Fluid Mechanics

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Hello, I need help with 13. Please and thank you.

In the depths of space, asteroid miners attach a cable between their 3,694.-kg spaceship and a relatively small 1476-kg
asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to “reel in" the asteroid under a constant tension
of 512.0 N. We are going to calculate how long it takes take for them to meet. This is a somewhat complicated question
involving several different concepts, so let's just take it step by step.
11.
Draw free-body diagrams for the asteroid, and for the spaceship.
Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively. i
(a) aa = 0.3469 m/s²; a, = 0.1386 m/s²
(b) aa = 0.1386 m/s²; a, = 0.3469 m/s²
(c) a, = 0.1388 m/s²; a̟ = 0.2775 m/s²
(d) aa = 0.2775 m/s²; a̟ = 0.1388 m/s²
12.
13.
Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship.
(a) 0.2083 m/s²
(b) 0.4163 m/s²
(c) 0.1387 m/s²
(d) 0.4855 m/s²
14.
Calculate the time it takes for the asteroid and the spaceship to arrive at the same location. G
(a) 104 s
(b) 84.9 s
(с) 60.1 s
(d) 55.6 s

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