14. What is the equation of the line perpendicular to =(x – 6) and passes through the point (-3,2)? (x + 3) O A. y - 2 = - O B. y +3 = -;(x – 2) Ос. у - 2 %3D3 (x+ 3) O D. y+3 =(x – 2)

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter8: Introduction To Functions
Section8.10: Inverse Variation
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14. What is the equation of the line perpendicular to
2
y – 4 = (x – 6) and passes through the point
(-3,2)?
5
O A. y - 2 = -;(x+ 3)
O B. y +3 = -;(x – 2)
Ос. у -2 %3D (x + 3)
O D. y +3 =(x – 2)
2
5
5
2
Transcribed Image Text:14. What is the equation of the line perpendicular to 2 y – 4 = (x – 6) and passes through the point (-3,2)? 5 O A. y - 2 = -;(x+ 3) O B. y +3 = -;(x – 2) Ос. у -2 %3D (x + 3) O D. y +3 =(x – 2) 2 5 5 2
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