14. Write the equation of the hyperbola centered at (4, 2). The length of the vertical transverse axis is 3 and length of the conjugate axis is 7. (x-4)2 A. (y-2)² = 1 (x-4)² C. (у-2)2 = 1 25 25 4 (y-2)² (x-4)² = 1 (y-2)² D. 49 (x-4)² = 1 В. 49 4

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 33E
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answer the three subparts (14, 15, 16) Answers ONLY.

14. Write the equation of the hyperbola centered at (4, 2). The length of the vertical
transverse axis is 3 and length of the conjugate axis is 7.
(x-4)²
A.
(y-2)²
= 1
(х-4)2
С.
(y-2)²
= 1
-
25
25
4
(y-2)²
В.
(x-4)²
= 1
(y-2)2
D.
(x-4)²
= 1
49
49
4
15. Find the equation of the ellipse that has a center at (9,4), a focus at (5,4), and a vertex at
(4, 4).
(x-9)2
A.
(y-4)*
= 1
16
(x-9)²
C.
(у-4)4
= 1
16
25
36
(х-9)2
+
36
(y-4)*
(x-9)²
В.
25
(y-4)4
= 1
9
D.
= 1
25
16. Write an equation of a parabola whose directrix is x = 7 and has a focus at (-3, -7).
A. (y – 2)2 = -12(x+ 7)
B. (x + 7)2 = -25(y – 2)
C. (x – 2)² = -16(y+ 7)
D. (y + 7)² = -20(x – 2)
Transcribed Image Text:14. Write the equation of the hyperbola centered at (4, 2). The length of the vertical transverse axis is 3 and length of the conjugate axis is 7. (x-4)² A. (y-2)² = 1 (х-4)2 С. (y-2)² = 1 - 25 25 4 (y-2)² В. (x-4)² = 1 (y-2)2 D. (x-4)² = 1 49 49 4 15. Find the equation of the ellipse that has a center at (9,4), a focus at (5,4), and a vertex at (4, 4). (x-9)2 A. (y-4)* = 1 16 (x-9)² C. (у-4)4 = 1 16 25 36 (х-9)2 + 36 (y-4)* (x-9)² В. 25 (y-4)4 = 1 9 D. = 1 25 16. Write an equation of a parabola whose directrix is x = 7 and has a focus at (-3, -7). A. (y – 2)2 = -12(x+ 7) B. (x + 7)2 = -25(y – 2) C. (x – 2)² = -16(y+ 7) D. (y + 7)² = -20(x – 2)
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