15-16. In the fruit fly, vestigial (tiny) wings and hairy body are produced by recessive genes. The normal alleles, long wings and hairless body, are dominant. If a vestigial- winged male heterozygous for hairless is crossed with a hairy female heterozygous for long wings, what will be the phenotypic ratio of the F1? F2Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Genotypes = 1/4 NnHh 1/4 Nnhh 1/4 nnHh 1/4 nnhh = 1:1:1:1 ratio F1 Phenotypes = All normal wings/hairy = 1:0 ratio

15-16. In the fruit fly, vestigial (tiny) wings and hairy body are produced by recessive genes. The normal alleles, long wings and hairless body, are dominant. If a vestigial- winged male heterozygous for hairless is crossed with a hairy female heterozygous for long wings, what will be the phenotypic ratio of the F1? F2Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Genotypes = 1/4 NnHh 1/4 Nnhh 1/4 nnHh 1/4 nnhh = 1:1:1:1 ratio F1 Phenotypes = All normal wings/hairy = 1:0 ratio

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Description: 15-16. In the fruit fly, vestigial (tiny) wings and hairy body are produced by recessivegenes. The normal alleles, long wings and hairless body, are dominant. If a vestigial-winged male heterozygous for hairless is crossed with a hairy female hetero

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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Having malformed hands with shortened fingers is a dominant trait controlled by a single gene; people who are homozygous for the recessive allele have normal hands and fingers. Having woolly hair is a dominant trait controlled by a different gene; homozygous recessive individuals have normal, nonwoolly hair. Suppose a woman with normal hands and nonwoolly hair marries a man who has malformed hands and woolly hair. Their first child has normal hands and nonwoolly hair. What are the genotypes of the mother, the father, and the child? If this couple has a second child, what is the probability that it will have normal hands and woolly hair?
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Ch. 13-8 In sweet pea plants, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (l). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains.All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes:296 purple flowers/long pollen grains19 purple flowers/round pollen grains27 red flowers/long pollen grains85 red flowers/round pollen grainsWhat is the best explanation for these results?
7 Cinnabar eyes is a X-linked recessive characteristic in fruit flies. If a female having cinnabar eyes is crossed with a normal wild-type male, what percentage of the F1 males will have cinnabar eyes?
9. Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
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7-5. In corn a pair of genes determines leaf shape and another pair determines pollen shape. A ragged-leafed plant with round pollen was crossed to a ragged-leafed plant with angular-pollen, and the resultant progeny were classified as follows: Class Phenotypes 186 ragged-leaf round-pollen 11 IV 174 ragged-leaf angular-pollen 57 smooth-leaf round-pollen Total 63/480 smooth-leaf angular-pollen (a) Using alphabetical letters of your choice, designate the genes for the different leaf and pollen characters. (b) On the basis of the symbols given in (a) 1 provide genotypes two parents. (c) (forth)/(nbers) According to your hypothesis what would you have expected for each of the four classes of progeny? (d) After re viewing Chapter 8, use the chi-square method (p. 132) to test your hypothesis and indicate whether you accept or reject it.