152A hw - 13Torque, Rotational Dynamics and Angular Momentum1. Four forces are acting on a light and uniform rod of length L = 2.0 m, as shown.Consider F1 10 N, a 25 °, F2 15 N, acting at the c.m., F3 20 N, B= 40°,and F4 25 N, y= 60°. Find the net torque on the rod for each axis A, B, C andD.F&F1F3ВInotisvnВTС1.5 mF2ub2. A uniform sphere (r - 30 cm) is rolling without slipping on a flat surface at aconstant velocity (i.e., vcm is constant)

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Asked Nov 14, 2019
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How do you find the net torque on axis A, B, C, and D?

15
2A hw - 13
Torque, Rotational Dynamics and Angular Momentum
1. Four forces are acting on a light and uniform rod of length L = 2.0 m, as shown.
Consider F1 10 N, a 25 °, F2 15 N, acting at the c.m., F3 20 N, B= 40°,
and F4 25 N, y= 60°. Find the net torque on the rod for each axis A, B, C and
D.
F&
F1
F3
В
Inotisvn
В
T
С
1.5 m
F2
ub
2. A uniform sphere (r - 30 cm) is rolling without slipping on a flat surface at a
constant velocity (i.e., vcm is constant)
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15 2A hw - 13 Torque, Rotational Dynamics and Angular Momentum 1. Four forces are acting on a light and uniform rod of length L = 2.0 m, as shown. Consider F1 10 N, a 25 °, F2 15 N, acting at the c.m., F3 20 N, B= 40°, and F4 25 N, y= 60°. Find the net torque on the rod for each axis A, B, C and D. F& F1 F3 В Inotisvn В T С 1.5 m F2 ub 2. A uniform sphere (r - 30 cm) is rolling without slipping on a flat surface at a constant velocity (i.e., vcm is constant)

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Step 1

The below figure represents four force acting on light and uniform rod.

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В 1.5 m С A F2

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Step 2

considering positive value for torque acting in clockwise direction , and negative value for torque acting in anticlockwise direction .

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Given that the length of the rod is L = 2.0m F 10N and a=25° F 15N F 20 N and B-40° F 25N andy=60° 4 The general expression for torque is given by ] = Frsin 0 The net torque on the rod at axis A is given by - F(0m)+ F,(Im)sin 90°- F,(1.55m)sin 40° - F, (2m)sin (90° + 60°) A 1 TA 0+15m(1m(20 N) (1.55m) (0.643)-(25 N) (2m)x 2 TA-29.29N/m [2]

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Step 3

Write the net torque on...

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The net torque on the rod at axis B is given by B F(1m)sin a F, (0.5m)sin B- F,(1m)sin (90° +60°) 3 4 1 -(10N) (1m)sin 250 - (20 N) (0.5m)(sin 40°)- (25 N) (1m) x 2 T(4.23-6.43-12.5)N/m T3=-14.7 N/m [2]

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