Do question 15 PORST is a regular pentagon (i.e. a plane figurewith 5 equal sides) inscribed in a circlecentre O. radius 37 cm. M is the mid-point of29.9 cm.%3DRS and MO(a) Calculate: (i) MR(b) Hence, determine the perimeter of the(ii) RSpentagon.15.9.5 mAC18.2 m-Fig. 9.214 End of a houseFig. 9.214 illustrates the cross-section of abuilding of width DE = 18.2 m and roof slopeAB = 9.5 m. Calculate the altitude BF of the roof.%3DQuadrilateralA quadrilateral is a plane shape (or figure) boundedby four straight lines.A quadrilateral can also be defined as a fouraridodpolygon.

Given : Now from the given figure, we get AC=ED=18.2 m F is the mid-point of AC Therefore, AF=…

Answered: 15. 9.5 m D. -18.2 m-

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter65: Achievement Review—section Six

Section: Chapter Questions

Problem 56AR

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The tin can shown at the right has the indicated dimensions. Estimate the number of square inches of tin required for its construction. HINT: Include the lid and the base in the result.
A rectangular solid has length L=12.6 mm, width W=23.8 mm, and height H=32.5 mm. Find the length of a diagonal AB from the upper left rear vertex to the lower right front vertex. Round the answer to 1 decimal place.
A diagonal of a cube joins two vertices so that the remaining points of the diagonal lie in the interior of the cube. Show the diagonal of the cube having edges of length e is e3 units long.
The surface of a soccer ball is composed of 12 regular pentagons and 20 regular hexagons. With each side of each regular polygon measuring 4.5 cm, the area of each regular pentagon is 34.9 cm2 and area of each regular hexagon is 52.5 cm2. a What is the surface area of the soccer ball? b If the material used to construct the ball costs 0.8 of a cent per square centimeter, what is the cost of the materials used in construction?
Tsunami Waves and BreakwatersThis is a continuation of Exercise 16. Breakwaters affect wave height by reducing energy. See Figure 5.30. If a tsunami wave of height H in a channel of width W encounters a breakwater that narrows the channel to a width w, then the height h of the wave beyond the breakwater is given by h=HR0.5, where R is the width ratio R=w/W. a. Suppose a wave of height 8 feet in a channel of width 5000feet encounters a breakwater that narrows the channel to 3000feet. What is the height of the wave beyond the breakwater? b. If a channel width is cut in half by a breakwater, what is the effect on wave height? 16. Height of Tsunami WavesWhen waves generated by tsunamis approach shore, the height of the waves generally increases. Understanding the factors that contribute to this increase can aid in controlling potential damage to areas at risk. Greens law tells how water depth affects the height of a tsunami wave. If a tsunami wave has height H at an ocean depth D, and the wave travels to a location with water depth d, then the new height h of the wave is given by h=HR0.25, where R is the water depth ratio given by R=D/d. a. Calculate the height of a tsunami wave in water 25feet deep if its height is 3feet at its point of origin in water 15,000feet deep. b. If water depth decreases by half, the depth ratio R is doubled. How is the height of the tsunami wave affected?
Cycling The Campagnolo Hyperon Ultra Two carbon wheel, which has a diameter of 700 millimeters, has 22 spokes evenly distributed around the rim of the wheel. What is the length of the rim subtended by adjacent pairs of spokes (Figure 15)?

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