Please help 16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g)[CH,Cl2] [H,]K(CH; Cl] [CL,]CH,Ch]" [H,K =16168[CH,CI" (CL,16K =16[CH,Cl,]" [H,][CH3 CI] [CL,][CH,C12] [H,]K =(CH,C1] (CL,]CH2Cl2] (H,]K =

Choose the corect option for Kc expression ---

16 CH3CI(g) + 8 Cl2(g) → 16 CH2CI2(g) + 8 H2(g) K - CH,Cl,] [H] [CH2 CI] [Cl,] CH,Cl]" [H," K = 16 (CH,C1]® [CL,j* [CH,C1" (CL,* K = 16 [CH,Cl2]" [H,]* [CH3CI] [CL,] [CH,C12] [H,] K = (CH,CI]/? (CL,] CH2Cl2] (H,] K =

16 CH3CI(g) + 8 Cl2(g) → 16 CH2CI2(g) + 8 H2(g) K - CH,Cl,] [H] [CH2 CI] [Cl,] CH,Cl]" [H," K = 16 (CH,C1]® [CL,j* [CH,C1" (CL,* K = 16 [CH,Cl2]" [H,]* [CH3CI] [CL,] [CH,C12] [H,] K = (CH,CI]/? (CL,] CH2Cl2] (H,] K =

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter5: Thermochemistry

Section: Chapter Questions

Problem 5.50QE

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Question

Please help

16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g)
[CH,Cl2] [H,]
K
(CH; Cl] [CL,]
CH,Ch]" [H,
K =
16
16
8
[CH,CI" (CL,
16
K =
16
[CH,Cl,]" [H,]
[CH3 CI] [CL,]
[CH,C12] [H,]
K =
(CH,C1] (CL,]
CH2Cl2] (H,]
K =

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