16. x²y" (x) + 5xy' (x) + 4y(x) = 0 ; y (1) = 3, y' (1) = 7 17. x³y"(x) + 6x²y"(x) +29xy' (x) - 29y(x) = 0; y (1) = 2, y' (1) = -3, y"(1) = 19

Calculus: Early Transcendentals
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 16 pls Section 8.5
tions. As we will see, operator methods similar to those
the desired second solution.
m
on
F5
In Problems 15-17, solve the given initial value problem.
15. t²x"(t) — 12x(t) = 0 ;
x(1) = 3, x' (1) = 5
16. xy"(x) + 5xy' (x) + 4y(x) = 0;
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y (1) = 3, y' (1) = 7
17. x³y" (x) + 6x²y" (x) +29xy' (x) - 29y(x) = 0;
y (1) = 2, y' (1) = -3, y" (1) = 19
I
18. Suppose ro is a repeated root of the auxiliary equation
ar² + br+c= 0. Then, as we well know, y₁ (t) =
erot
is a solution to the equation ay" + by' + cy = 0, where
a, b, and c are constants. Use a derivation similar to the
one given in this section for the case when the indicial
equation has a repeated root to show that a second lin-
early independent solution is y2 (t) = teot.
19. Let L[y] (x)
x³y" (x) + xy' (x) − y(x).
(a) Show that L[x] (x) = (r-1)³x².
(b) Using an extension of the argument given in this
section for the case when the indicial equation
has a double root, show that L[y] = 0 has the
F6
DD
Transcribed Image Text:tions. As we will see, operator methods similar to those the desired second solution. m on F5 In Problems 15-17, solve the given initial value problem. 15. t²x"(t) — 12x(t) = 0 ; x(1) = 3, x' (1) = 5 16. xy"(x) + 5xy' (x) + 4y(x) = 0; Update Apple ID Settings Some account services will not available until you sign in again. y (1) = 3, y' (1) = 7 17. x³y" (x) + 6x²y" (x) +29xy' (x) - 29y(x) = 0; y (1) = 2, y' (1) = -3, y" (1) = 19 I 18. Suppose ro is a repeated root of the auxiliary equation ar² + br+c= 0. Then, as we well know, y₁ (t) = erot is a solution to the equation ay" + by' + cy = 0, where a, b, and c are constants. Use a derivation similar to the one given in this section for the case when the indicial equation has a repeated root to show that a second lin- early independent solution is y2 (t) = teot. 19. Let L[y] (x) x³y" (x) + xy' (x) − y(x). (a) Show that L[x] (x) = (r-1)³x². (b) Using an extension of the argument given in this section for the case when the indicial equation has a double root, show that L[y] = 0 has the F6 DD
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