(17) y "'- 3y "+ 3y '– y = x – 4e*

Q: y" – 4y' + 4y = 2.x² + 4xe²" + x sin(2x)

A: Given differential equation is

Q: + 1 =2e- dy

A: Given, Can be rewritten as

Q: How would I approach this problem algebraically, and analytically? I have attached a photo.

A: To find:

Q: dx dt -1 -3 [:] 2 with x(0) 4 Give your solution in real form.

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Q: 1 В(т, п) ym-1(a – y)"-'dy. am+n-1

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Q: Solve for separable equation xy +5y + 2x + 10 2xy - 10y -x +5 6. 2x + 3 -dy = 0 y - 6

A: The given differential equation is: xy+5y+2x+102x+3dx+2xy-10y-x+5y-6dy=0 To solve the differential…

Q: Solve by Chain Rule (V3x² + In(5X*)) y = tan

A: To differentiate the given function using chain rule.y=tan3x23+ln5x4

Q: d- . -x e-(x² +y²) dy dx -(x²+y²) dy dx

A: We can answer one question as per the honor policy. Please resubmit other question as well to know…

Q: 6. Solve (cotx - 1)(2cosx + 1) = 0 where 0° sxs 360°. Show your work. %3D

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Q: 5z² – VE 1+ tan(x) Find an dy when y = dr Do NOT simplify. expression for

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Q: solve using non-exact (x+4y3)dy - ydx = 0

A: Solving the non exact differential equation

Q: tan20 sec2ede In 2 edx 3. 1. (a² + a²tan²0)² 2ex- 1 x'dx dx x- 1 2. 4. (1+ x2)3

A: As per our policy, only the first three subdivisions will be solved. For the remaining subdivision,…

Q: 3. Find d²y/dx² of y= x cos (5x) – sin² x/ |

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Q: solve the differenhal equa hon by varianon of parameters y" + 3y't 2y 7 te* y (x)

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Q: Ssin(2x+3)dx= d -1 cos(2.x+ 3)+C 2 a 5 cos(2.x + 3)+C -1 cos(2x+3)+C - cos(2x+3)+ C e cos(2x +3)+ C

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Q: Only I method. Except Exact DE (x+2y-1)dx+(2x+4y-3)dy oo

A: First we campare the given differential equation Mdx+Ndy= 0 and then solve it.

Q: 5-(1+x')(dy-dx)= 2.xydx;

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Q: 6. (2z – 1)(y – 1)dr + (x+ 2)(x – 3)dy = 0, y(1) = -1

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Q: 7. (2x + 3y)dx + (3x + 2)dy = 0 When: x = 3, y = 2

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Q: y 2sin x-cos 2.x for 0° sxs360

A: Consider the function, y=2sinx-cos2x Differentiate with respect of x,…

Q: 2 Find So (3x2 + 4y³) dy dx.

A: Topic:- double integration

Q: | cos 3y dy 4.

A: I=∫ cos6(3y) dy3y=tdy=t3Integration by parts;∫uv dx=u∫v dx -∫ dudx ∫vdx dxI=13 ∫ cos6t…

Q: xdx S- can be solved by either algebraic subsitution or integrataion by parts. Vx-1

A: We have to find the following integral

Q: Jz{sinh³ 4z*)'^ ² - dz 1/4 cosh³ 4z'

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Q: d’y - 2 y = 5x' + In(x²). dx

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Q: 3. f(x,y) tanx - sec²x - cosy

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Q: x7= - 3x + 18 JZ - 54 in (3+ 57) + c 3/2 2 dx = %3D 3 + VX 3

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Q: y" + 4y = 2 sin(6x)+ 6x²e¬3z + 5x,

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Q: 2. (бх * у) dx +у (2х - Зу) dy 3 0

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Q: Intergrate:

A: To evaluate the integral.

Q: Solve for particular solution. (2x-6y+4)dx + (x-2y-3)dy = 0 ; when x = 1, y = 1

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Q: Find the differential dy. y = cubic root of 3x^2

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Q: 17 (7+ x²^ dy when y = dx Find %3| 7 – x²

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Q: (3– 3cos5x)} (3x² +2x-7)² (e - sinx +3x) y= Find dy/dx if

A: That's computational, take a careful look.

Q: 3 sin(3x) 2cos (4y) dy dx (-)= 3 4

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Q: 1. (2x -х-у)dx- хdy - 0; y(1) -о

A: Given that: (2x2-x-y)dx-xdy=0; y(1)=0

Q: 22 32 S[ (4-y ) dydx 1. ans:- 3 0 0

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Q: 14-2x 1. ! ] dydx 0 2 2. dxdy 0 y 11-r 3. dycx o 1-x 4. [[ dydx 0 0

A: Answer 1: changing dy dx to dx dy; limits of integration: 0 ≤ x ≤  [2 - (y/2)] 2 ≤ y ≤ 4

Q: By differentiating x² – y² = 1 implicitly, show that d²y | dx² ||

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Q: ly 3)[e^(-2y)]dy

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Q: 1,- X73X+2 dx (x+リ) Izafhinx dx Ax. Iォfュース alx dx X43X+2 X+1

A: Since, you have posted multiple, we will solve only first part. If you want solution of other…

Q: 3z (sec-(-3z?))³ 2|–3z*|-/9zª–1 If y= sec-1 (-3x²), then dy dz

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Q: 3) Find d²y/dx² at the point (1, 1), if x6 + y6 = 2.

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Q: sin(3z+z²) Find y' for y = (6 – 2*)3

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Q: 9-y dy 5. S y

A: We will use trigonometric substitution.

Q: f(x csc² 2x - x cos 2x)dx

A: The given integral is ∫xcsc22x-xcos2xdx. The objective is to solve the given integral. Following…

Q: /25-x2 V25-x2 -y2 1 dz dy dx -/25–x² -V25-x² -y²

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Q: dèy 6. dx2 1-cos4x if y = 1+cos4x

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