17. 4NH3(g) + 302(g) → 2N2(g) + 6H20(g)Calculate the following, with proper number of significant figures:When 0.24 mol of O2 react,liters at STP of NH3 react also.For 3020 liters at STP of N2 form,liters at STP of NH3 must react.For 9.20 grams of H20 to form,liters at STP of O2 must react.

At STP, volume of 1 mole = 22.4 L

17. 4NH;(g) + 302(g) → 2N2(g) + 6H20(g) Calculate the following, with proper number of significant figures: When 0.24 mol of O, react, liters at STP of NH3 react also. For 3020 liters at STP of N2 form, liters at STP of NH3 must react For 9.20 grams of H20 to form, liters at STP of O2 must react.

17. 4NH;(g) + 302(g) → 2N2(g) + 6H20(g) Calculate the following, with proper number of significant figures: When 0.24 mol of O, react, liters at STP of NH3 react also. For 3020 liters at STP of N2 form, liters at STP of NH3 must react For 9.20 grams of H20 to form, liters at STP of O2 must react.

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter13: Gases

Section: Chapter Questions

Problem 78A

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

17. 4NH3(g) + 302(g) → 2N2(g) + 6H20(g)
Calculate the following, with proper number of significant figures:
When 0.24 mol of O2 react,
liters at STP of NH3 react also.
For 3020 liters at STP of N2 form,
liters at STP of NH3 must react.
For 9.20 grams of H20 to form,
liters at STP of O2 must react.

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