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17. Calculate the equilibrium constant, Kp, at 298 K for the 3rd reaction. 2 NO(g) + Br₂(g) 2 NOBr(g) Kc = 2.054 2 NO(g) N₂(g) + O₂(g) N₂(g) + O₂(g) + Br₂(g) 2 NOBr(g) Kc -9.401x10-31

17. Calculate the equilibrium constant, Kp, at 298 K for the 3rd reaction. 2 NO(g) + Br₂(g) 2 NOBr(g) Kc = 2.054 2 NO(g) N₂(g) + O₂(g) N₂(g) + O₂(g) + Br₂(g) 2 NOBr(g) Kc -9.401x10-31

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 71GQ: The equilibrium constant for the butane iso-butane equilibrium at 25 C is 2.50. Calculate rG at...
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17. Calculate the equilibrium constant, Kp, at 298 K for the 3rd reaction. 2 NO(g) + Br₂(g) 2 NOBr(g) Kc = 2.054 2 NO(g) N₂(g) + O₂(g) N₂(g) + O₂(g) + Br₂(g) 2 NOBr(g) Kc -9.401x10-31
Transcribed Image Text:17. Calculate the equilibrium constant, Kp, at 298 K for the 3rd reaction. 2 NO(g) + Br₂(g) 2 NOBr(g) Kc = 2.054 2 NO(g) N₂(g) + O₂(g) N₂(g) + O₂(g) + Br₂(g) 2 NOBr(g) Kc -9.401x10-31
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