17. ~[(pvq) ~q]
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- Transcribed Image Text DNA is sequence of bases A, G, T, C. Let DNA [ab] be the subsequence of DNA starting from index a finishing in b inclusive, and DNA[a.] be the subsequence of DNA starting from index a to the end. We could perform the following ops on DNAS: cross operation - they take DNA1 and DNA2 and numbers kl and k2. Then two new DNAS are created: DNA3 = DNA1[1,,k1]+DNA2[k2+1.] and DNA4 = DNA2[1.k2]+DNA1[k1+1.].mutate operation - they take a DNA, number k and one of the bases. Then they replace the base in position k in DNA with that base. also, they need to know certain characteristics of those DNAS. So, they can perform count operation - they take DNA and numbers k1 and k2 (k1 <= k2). This operation should return the number of A, G, T, C bases in DNA[k1,,k2].The initial DNAS are numbered from 1 to n, where n is the amount of those DNAS. The new DNAS the first line of input file contains number n - the number of initial DNAS. Each of the following n lines containsUSE C++ (Display matrix of 0s and 1s) Write a function that displays an n-by-n matrix using the following header: void printMatrix(int n) Each element is 0 or 1, which is generated randomly. Write a test program that prompts the user to enter n and displays an n-by-n matrix. Here is a sample run:(C Language) The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1.
- Dec2Hex function : def decimal_to_hex(number): hex_map = {0: '0', 1: '1', 2: '2', 3: '3', 4: '4', 5: '5', 6: '6', 7: '7', 8: '8', 9: '9', 10: 'A', 11: 'B', 12: 'C', 13: 'D', 14: 'E', 15: 'F'} hex_digits = [] while number > 0: hex_digits.append(hex_map[number % 16]) number //= 16 # Reverse the order of the hex digits and join them to form the final hex string hex_string = ''.join(reversed(hex_digits)) return f'0x{hex_string}' if hex_string else '0x0' Perform a Profile of your Dec2Hex function. Write a function that takes a timedate object as a parameter andcalculates the number of years from NOW to the time in the timedateobject. Add unit-testing code to your Dec2Hex exercise, and then perform aUnit test of the updated Dec2Hex code.Computer Science Written in C, if I have a global 2d array [256][10] and it is already filled with 0's & 1's, write in C to show how I would use bitwise operators to write them to a file to make the file compressed.1/ I need coding with output). Take as You are given a list of queries, each consisting of three integers: a, b, and k. Your task is to perform a series of operations on an array of size n such that each element in the array is incremented by k in a specific range defined by a and b. E;.
- ii) WAP to demonstrate the use of foreach loop on an array of strings, declare an array of strings and print all strings in output using foreach loop only. In Perl programming language.#include <bits/stdc++.h>using namespace std;int main() { double matrix[4][3]={{2.5,3.2,6.0},{5.5, 7.5, 12.6},{11.25, 16.85, 13.45},{8.75, 35.65, 19.45}}; cout<<"Input no in first row of matrix"<<endl; for(int i=0;i<3;i++){ double t; cin>>t; matrix[0][i]=t; } cout<<"Contents of the last column in matrix"<<endl; for(int i=0;i<4;i++){ cout<<matrix[i][2]<<" "; } cout<<"Content of first row and last column element in matrix is: "<<matrix[0][3]<<endl; matrix[3][2]=13.6; cout<<"Updated matrix is :"<<endl; for(int i=0;i<4;i++){ for(int j=0;j<3;j++){ cout<<matrix[i][j]<<" "; }cout<<endl; } return 0;} Please explain this codeWrite a c++ function is called IsContain Given two arrays A and B with equal size n, write a C++ function that returns true if every element of A is found in B; otherwise returns false
- change this code to C++ #include <stdio.h> #include <stdlib.h> /** * structure to hold each point */ struct Point3D { float x; float y; float z; }; /** * Parses all the vertices from the path. * @param path The input file path. * @param points The points storage. * @param numPoints The number of points. * @return points Dynamically allocated array of points. * @return The center of mass. */ struct Point3D parseInput(const char *path, struct Point3D **points, int *numPoints) { // to hold each record char f_or_v; float x; float y; float z; // to store the file pointer FILE *inFile; // to iterate the points array int it; // structure to store the center of mass struct Point3D centerOfMass; // opening the file inFile = fopen(path, "r"); // counting the number of points *numPoints = 0; while(!feof(inFile)) { fscanf(inFile, "%c %f %f %f\n", &f_or_v, &x, &y, &z); *numPoints += f_or_v == 'v'; } // dynamically allocating space // for the points *points =…The following numbers are inserted into an empty LLRBT in the given order: 11, 2, 14, 25, 15, 13, 16. Please draw the resulting LLRBT.U={A,B,C,D,E,F}, A={A,B,D,E}, B={B,C,E,F}, and C={A,B,C,D} complete the following set operations: 1(A'n B) uC' 2. A n (Bu C;)